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2 years ago

The point nearest to the origin on a line is at (4, -4). Find the standard form of the equation of the line.

Mathematics

1 answer:

NikAS [45]2 years ago

5 0

Answer:

I think it's C, x-y-8=0

Step-by-step explanation:

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What is the fraction 18/24 reduce to its lowest terms

zaharov [31]

$\frac{18}{24} = \frac{6\times 3}{6\times 4} = \boxed{\frac{3}{4}}$

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3 years ago

PLEASE HELP I WILL GIVE BRAINLIEST TO QUICKEST RESPONSE

musickatia [10]

Answer:

2.3

Step-by-step explanation:

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2 years ago

Read 2 more answers

How can I find the exact distance between the points(√7,-√2)and (4√7,5√2)

chubhunter [2.5K]

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ \sqrt{7}}}\quad ,&{{ -\sqrt{2}}})\quad 
% (c,d)
&({{4\sqrt{7}}}\quad ,&{{ 5\sqrt{2}}})
\end{array}~~~
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
$

$\bf d=\sqrt{[4\sqrt{7}-\sqrt{7}]^2~+~[5\sqrt{2}-(-\sqrt{2})]^2}
\\\\\\
d=\sqrt{(4\sqrt{7}-\sqrt{7})^2~+~(5\sqrt{2}+\sqrt{2})^2}\implies d=\sqrt{(3\sqrt{7})^2~+~(6\sqrt{2})^2}
\\\\\\
d=\sqrt{3^2\cdot 7~~+~~6^2\cdot 2}\implies d=\sqrt{63+72}\implies d=\sqrt{135}
\\\\\\
\begin{cases}
135=5\cdot 3\cdot 3\cdot 3\\
\qquad 5\cdot 3^2\cdot 3\\
\qquad 15\cdot 3^2
\end{cases}\implies d=\sqrt{15\cdot 3^2}\implies d=3\sqrt{15}$

8 0

3 years ago

I WILL MARK BRAINIEST <br> PLEASE ANSWER QUESTION 22

ella [17]

Answer:

blank 1: 3x

blank 2: 3y

blank 3: dilation?

Step-by-step explanation:

Honestly for these I don't think I have enough information. There could be multiple answers

8 0

2 years ago

Convert 42.4 inches to meters.Round your answer to 2 decimal points

Naya [18.7K]

Answer:

1.07m

Step-by-step explanation:

the first step is to convert inches to cm

1in =2.54cm

(42.4in/1in x2.54cm)

42.4in = 107.69cm

then convert cm to m

1cm =0.01m

(107.69cm/1cm x 0.01m)

107.69cm =1.0769m

~1.07m

4 0

2 years ago