I do not know how to work this out... can someone PLEASE help me???

Mathematics

2 answers:

Zolol [24]3 years ago

4 0

= square root 11 (5 - 12 - 2)
= square root 11(-9)
= -9 square root 11

answer is C.
you got it right

olga2289 [7]3 years ago

3 0

5 of something - 12 of the same thing - 2 of the same thing
= 5 of x - 12 of x - 2 of x
=5x-12x-2x
=x(5-12-2)
=-9x

$5 \sqrt{11} -12 \sqrt{11} -2 \sqrt{11} \\~\\=( \sqrt{11} )(5-12-2)\\~\\-9 \sqrt{11}$

I hope you got the idea!

You might be interested in

Please help me with this question.

ruslelena [56]

Answer:

Step-by-step explanation:

-1 ≤ x < 3 Solution set = {-1, 0 ,1 , 2}

-2 < x < 2 Solution set = {-1 , 0 , 1}

Integer values that satisfies both inequalities are -1 , 0 , 1

6 0

2 years ago

Read 2 more answers

Quadratics need help making parabola

timama [110]

Answer:

The equation of the parabola is $y = \frac{1}{3}\cdot x^{2}-\frac{4}{3}\cdot x -4$ , whose real vertex is $(x,y) = (2, -5.333)$ , not $(x,y) = (2, -5)$ .

Step-by-step explanation:

A parabola is a second order polynomial. By Fundamental Theorem of Algebra we know that a second order polynomial can be formed when three distinct points are known. From statement we have the following information:

$(x_{1}, y_{1}) = (-2, 0)$ , $(x_{2}, y_{2}) = (6, 0)$ , $(x_{3}, y_{3}) = (0, -4)$

From definition of second order polynomial and the three points described above, we have the following system of linear equations:

$4\cdot a -2\cdot b + c = 0$ (1)

$36\cdot a + 6\cdot b + c = 0$ (2)

$c = -4$ (3)

The solution of this system is: $a = \frac{1}{3}$ , $b = - \frac{4}{3}$ , $c = -4$ . Hence, the equation of the parabola is $y = \frac{1}{3}\cdot x^{2}-\frac{4}{3}\cdot x -4$ . Lastly, we must check if $(x,y) = (2, -5)$ belongs to the function. If we know that $x = 2$ , then the value of $y$ is: