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il63 [147K]
3 years ago
9

I do not know how to work this out... can someone PLEASE help me???

Mathematics
2 answers:
Zolol [24]3 years ago
4 0
= square root 11 (5 - 12 - 2)
= square root 11(-9)
= -9 square root 11

answer is C.
you got it right
olga2289 [7]3 years ago
3 0
5 of something - 12 of the same thing  - 2 of the same thing
= 5 of x - 12 of x - 2 of x
=5x-12x-2x
=x(5-12-2)
=-9x

5 \sqrt{11} -12 \sqrt{11} -2 \sqrt{11} \\~\\=( \sqrt{11} )(5-12-2)\\~\\-9 \sqrt{11}


I hope you got the idea!



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Step-by-step explanation:

<u>Given:</u>

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<u>Use tangent to solve for h:</u>

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Answer:

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Step-by-step explanation:

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\triangle CAE -- Bigger Triangle

\triangle CBD -- Smaller Triangle

k = \frac{4}{3} --- Scale factor

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Required

Determine the area of CAE

The area of triangle CBD is:

A_1 = \frac{1}{2}bh

\frac{1}{2}bh = 9

The area of CAE is:

A_2 = \frac{1}{2}BH

Where:

B = \frac{4}{3}b and

H = \frac{4}{3}h

The above values is the dimension of the larger triangle (after dilation).

So, we have:

A_2 = \frac{1}{2}*\frac{4}{3}b * \frac{4}{3} * h

A_2 = \frac{1}{2}*\frac{4}{3} * \frac{4}{3} *b* h

A_2 = \frac{1}{2}*\frac{16}{9}  *b* h

Re-order

A_2 = \frac{16}{9}*\frac{1}{2}* b* h

A_2 = \frac{16}{9}*\frac{1}{2}bh

Recall that:

\frac{1}{2}bh = 9

A_2 = \frac{16}{9}*9

A_2 = 16

Hence, the area is 16 cm^2

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