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3 years ago

- 113 x (-4) =plz no links

Mathematics

1 answer:

Rudiy273 years ago

7 0

Answer:

452

Step-by-step explanation:

Have a Wonderful day

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PLEASE HURRY I'M BEING TIMED

kobusy [5.1K]

Answer:

i think the answer is D my guy

Step-by-step explanation:

do you need the steps??

mark brainliest :p

6 0

3 years ago

1200 mm long and 800 mm wide. What is the area in square meters

alexgriva [62]

Answer: $0.96\ m^2$

Step-by-step explanation:

We can make the conversion from milimeters to meters (Remember that $1m=1,000\ mm$ ). Then:

$1,200\ mm$ to $m$ :

$(1,200\ mm)(\frac{1\ m}{1,000\ mm})=1.2\ m$

$800\ mm$ to $m$ :

$(800\ mm)(\frac{1\ m}{1,000\ mm})=0.8\ m$

Now, we need to use this formula for calculate the area of a rectangle:

$A=lw$

Where "l" is the lenght and "w" is the width.

Knowing that:

$l=1.2\ m\\w=0.8\ m$

We can substitute values into the formula. Then we get:

$A=(1.2\ m)(0.8\ m)\\\\A=0.96\ m^2$

3 0

3 years ago

Help me, please I don't wanna fail highschool

AVprozaik [17]

10800=1000p. Divide 10800/1000=p. P=10.8.

8 0

3 years ago

Read 2 more answers

A boat traveled 15O feet in 12 seconds how far would be the boat travel in 1

Lapatulllka [165]

Answer:

About 12.5 feet.

Step-by-step explanation:

You take 150feet and divide it by 12, once you do that you get 12.5 feet. to double check that you do 12.5 times 12 and you get 150

5 0

3 years ago

Find the imaginary part of\[(\cos12^\circ+i\sin12^\circ+\cos48^\circ+i\sin48^\circ)^6.\]

iren [92.7K]

Answer:

The imaginary part is 0

Step-by-step explanation:

The number given is:

$x=(\cos(12)+i\sin(12)+ \cos(48)+ i\sin(48))^6$

First, we can expand this power using the binomial theorem:

$(a+b)^k=\sum_{j=0}^{k}\binom{k}{j}a^{k-j}b^{j}$

After that, we can apply De Moivre's theorem to expand each summand: $(\cos(a)+i\sin(a))^k=\cos(ka)+i\sin(ka)$

The final step is to find the common factor of i in the last expansion. Now:

$x^6=((\cos(12)+i\sin(12))+(\cos(48)+ i\sin(48)))^6$

$=\binom{6}{0}(\cos(12)+i\sin(12))^6(\cos(48)+ i\sin(48))^0+\binom{6}{1}(\cos(12)+i\sin(12))^5(\cos(48)+ i\sin(48))^1+\binom{6}{2}(\cos(12)+i\sin(12))^4(\cos(48)+ i\sin(48))^2+\binom{6}{3}(\cos(12)+i\sin(12))^3(\cos(48)+ i\sin(48))^3+\binom{6}{4}(\cos(12)+i\sin(12))^2(\cos(48)+ i\sin(48))^4+\binom{6}{5}(\cos(12)+i\sin(12))^1(\cos(48)+ i\sin(48))^5+\binom{6}{6}(\cos(12)+i\sin(12))^0(\cos(48)+ i\sin(48))^6$

$=(\cos(72)+i\sin(72))+6(\cos(60)+i\sin(60))(\cos(48)+ i\sin(48))+15(\cos(48)+i\sin(48))(\cos(96)+ i\sin(96))+20(\cos(36)+i\sin(36))(\cos(144)+ i\sin(144))+15(\cos(24)+i\sin(24))(\cos(192)+ i\sin(192))+6(\cos(12)+i\sin(12))(\cos(240)+ i\sin(240))+(\cos(288)+ i\sin(288))$

The last part is to multiply these factors and extract the imaginary part. This computation gives:

$Re x^6=\cos 72+6cos 60\cos 48-6\sin 60\sin 48+15\cos 96\cos 48-15\sin 96\sin 48+20\cos 36\cos 144-20\sin 36\sin 144+15\cos 24\cos 192-15\sin 24\sin 192+6\cos 12\cos 240-6\sin 12\sin 240+\cos 288$

$Im x^6=\sin 72+6cos 60\sin 48+6\sin 60\cos 48+15\cos 96\sin 48+15\sin 96\cos 48+20\cos 36\sin 144+20\sin 36\cos 144+15\cos 24\sin 192+15\sin 24\cos 192+6\cos 12\sin 240+6\sin 12\cos 240+\sin 288$

(It is not necessary to do a lengthy computation: the summands of the imaginary part are the products sin(a)cos(b) and cos(a)sin(b) as they involve exactly one i factor)

A calculator simplifies the imaginary part Im(x⁶) to 0

4 0

3 years ago

- 113 x (-4) =plz no links​

- 113 x (-4) =plz no links