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Veronika [31]
3 years ago
10

Find cos(a) in the triangle.

Mathematics
1 answer:
pickupchik [31]3 years ago
7 0

{\huge{\boxed{\mathcal{\green{ANSWER}}}}} \\ cos( \alpha ) = base \div hypotenuse \\  \\ base \:  =  \: 21 \\  \\ hypotenuse = 29 \\  \\ cos( \alpha ) = 21 \div 29 \\  \\ {\huge{\boxed{\mathfrak{\red{hope \: it \: helps \: }}}}}

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Zaria wants you to solve this puzzle: “I am thinking of a number.
pshichka [43]

Answer:

first what you do is divide two and then for and then after you divide them together you can get your number so I'm going to show you example how to do it

Step-by-step explanation:

first divide 4 / 2 and then you can get your answer after you divide that

5 0
3 years ago
X+y+z=2<br> X-y-z=2<br> x-y+z=-6
likoan [24]
<h2>The first one:</h2>

<u>solve for x.</u>

Step 1: Add -y to both sides.

x+y+z+−y=2+−y

x+z=−y+2

Step 2: Add -z to both sides.

x+z+−z=−y+2+−z

<u>x=−y−z+2</u>

<u>solve for y.</u>

Step 1: Add -x to both sides.

x+y+z+−x=2+−x

y+z=−x+2

Step 2: Add -z to both sides.

y+z+−z=−x+2+−z

<u>y=−x−z+2</u>

<u>solve for z.</u>

Step 1: Add -x to both sides.

x+y+z+−x=2+−x

y+z=−x+2

Step 2: Add -y to both sides.

y+z+−y=−x+2+−y

<u>z=−x−y+2</u>

<u />

<h2>The second one:</h2>

<u>solve for x. </u>

Step 1: Add y to both sides.

x−y−z+y=2+y

x−z=y+2

Step 2: Add z to both sides.

x−z+z=y+2+z

<u>x=y+z+2</u>

<u>solve for y.</u>

Step 1: Add -x to both sides.

x−y−z+−x=2+−x

−y−z=−x+2

Step 2: Add z to both sides.

−y−z+z=−x+2+z

−y=−x+z+2

Step 3: Divide both sides by -1.

−y /−1  = −x+z+2 /−1

<u>y=x−z−2</u>

<u>solve for z.</u>

Step 1: Add -x to both sides.

x−y−z+−x=2+−x

−y−z=−x+2

Step 2: Add y to both sides.

−y−z+y=−x+2+y

−z=−x+y+2

Step 3: Divide both sides by -1.

−z /−1  =  −x+y+2 /−1

<u>z=x−y−2</u>

<u />

<h2>The third one:</h2>

<u>solve for x. </u>

Step 1: Add y to both sides.

x−y+z+y=−6+y

x+z=y−6

Step 2: Add -z to both sides.

x+z+−z=y−6+−z

<u>x=y−z−6</u>

<u>solve for y.</u>

Step 1: Add -x to both sides.

x−y+z+−x=−6+−x

−y+z=−x−6

Step 2: Add -z to both sides.

−y+z+−z=−x−6+−z

−y=−x−z−6

Step 3: Divide both sides by -1.

−y /−1  =  −x−z−6 /−1

<u>y=x+z+6</u>

<u>solve for z.</u>

Step 1: Add -x to both sides.

x−y+z+−x=−6+−x

−y+z=−x−6

Step 2: Add y to both sides.

−y+z+y=−x−6+y

z=−x+y−6

I hope this was helpful <3

3 0
3 years ago
What did you include in your response? Check all that
Fantom [35]
You can pick any of them it won’t hold it against you.
I do it all the time.
Have a good day
4 0
3 years ago
Read 2 more answers
Simplify this expression 3x+6x
Ierofanga [76]
Since both 3x and 6x have the variable x in it, we can just go ahead and add 3 and 6.

3x+6x=9x
4 0
3 years ago
Read 2 more answers
The Perimeter of rectangle DEFG is 120, ED=X, and FE=4x. What is the value of x?
Mazyrski [523]

Perimeter=120

ED=x (length)

FE=4x (breadth)

Perimeter of rectangle= 2(l+b)

Given,

2(x+4x)=120

2x+8x=120

10x=120

x=120÷10

x=12

Therefore, value of x is 12

6 0
3 years ago
Read 2 more answers
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