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3 years ago

If Eli showed a 8.9% ROI on his $8000.00 investment, how much was his return on his investment

2 answers:

6 0

8.9% is equal to 0.089 because a percent is over a 100. So, you can just multiply the ROI by the investment to get:

$0.089(8000) = 712$

Your answer is: $712.

nikitadnepr [17]3 years ago

4 0

$8,000.00 represents 100%

$ ? represents 8.9 %

cross multiply ?=8.9·8,000/100=712

answer is $712 ROI

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g In a certain rural county, a public health researcher spoke with 111 residents 65-years or older, and 28 of them had obtained

Marat540 [252]

Answer:

95% confidence interval for the percent of the 65-plus population that were getting the flu shot is [0.169 , 0.331].

Step-by-step explanation:

We are given that in a certain rural county, a public health researcher spoke with 111 residents 65-years or older, and 28 of them had obtained a flu shot.

Firstly, the Pivotal quantity for 95% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of residents 65-years or older who had obtained a flu shot = $\frac{28}{111}$ = 0.25

n = sample of residents 65-years or older = 111

p = population proportion of residents who were getting the flu shot

Here for constructing 95% confidence interval we have used One-sample z test for proportions.

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

95% confidence interval for p = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.25-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{111} } }$ , $0.25+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{111} } }$ ]

= [0.169 , 0.331]

Therefore, 95% confidence interval for the percent of the 65-plus population that were getting the flu shot is [0.169 , 0.331].

7 0

3 years ago

Grandma has 1/2 of her birthday cake left . she wants her 12 grandchildren to each get the same size piece of cake to take home

eimsori [14]

Answer: 1/24

Step-by-step explanation:

you need to use kcf ( keep the first fraction change division into multiplication and flip the other fraction)

turn 12 into 12/1 and then just divide.

1/2 x 1/12

= 1/24

6 0

3 years ago

Read 2 more answers

PLZ HELP 1 part out of 50 is milk fat.which type of milk has more milk fat per cup?

Darya [45]

Is it a multiple choice question?

3 0

3 years ago

Find the solution to the following problem: 16 = X – 7 X=??

Darya [45]

Answer:

-8/3

Step-by-step explanation:

3 0

2 years ago

Please do this question

crimeas [40]

It would be 16 more 6th graders that are not in either band or orchestra.
15 6th Graders in band
9 6th Graders in both classes
+18 6th Graders in orchestra
-----
42 6th Graders in either class

100 6th Graders in total
-42 6th Graders in either class
-------
58 6th Graders in neither class
58-42= 16 more 6th Graders that are not in either class
You're welcome :)

7 0

3 years ago