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sertanlavr [38]
3 years ago
6

This is part one of the problem I’m going to post the part two right after this

Mathematics
1 answer:
frez [133]3 years ago
3 0

Answer:

no

Step-by-step explanation:

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Please help!
tensa zangetsu [6.8K]
If the parabola has y = -4 at both x = 2 and x = 3, then since a parabola is symmetric, its axis of symmetry must be between x = 2 and x = 3, or at x = 5/2. Our general equation can then be:
y = a(x - 5/2)^2 + k
Substitute (1, -2): -2 = a(-3/2)^2 + k
-2 = 9a/4 + k
Substitute (2, -4): -4 = a(-1/2)^2 + k
-4 = a/4 + k
Subtracting: 2 = 2a, so a = 1. Substituting back gives k = -17/4.
So the equation is y = (x - 5/2)^2 - 17/4
Expanding: y = x^2 - 5x + 25/4 - 17/4
y = x^2 - 5x + 2 (This is the standard form.)
5 0
2 years ago
How would I solve this?
Lelu [443]

If you help me with my last question I will help you with this one

3 0
2 years ago
HELP PLEASE WITH THIS ASAP ASAP
Georgia [21]

Answer:

52

Step-by-step explanation:

62 - 42 = 20

20 / 2 = 10

42 + 10 = 52

52... i think :\

5 0
1 year ago
WILL MARK BRAINLIEST IF CORRECT!!!!
lozanna [386]

Answer:

yo mama

Step-by-step explanation:

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2 years ago
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