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2 years ago

Can someone plsss help me?!

Mathematics

1 answer:

MAXImum [283]2 years ago

3 0

Answer:

Angle A is 101

Angle B is 79

Angle C is 83

Angle D is 97

Step-by-step explanation:

Vertical angles are congruent, which applies to C.

Lines are parallel so 79 and angle B are the same

Angle a is 101 because its a supplementary angle

Angle D is 97 because its also a supplementary angle so you subtract 83 from 180.

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A train left for London, and 6 hours later, a car traveling 85 mph tried

lisov135 [29]

Answer:

99/hour

Step-by-step explanation:

7*85=585:6=99 ndjdjdjduxhskshuejsjs

7 0

3 years ago

Two angles in a triangle are 30 degrees and 40 degrees. Find the missing angle measure. Please show your math work step by step

brilliants [131]

Answer:

110

Step-by-step explanation:

Hello There!

If you didn't know the rule about angles in a triangle is that they have a sum of 180

So we can find the measure of the missing angle by subtracting the given angles (in this case 30 and 40) from 180

so the missing angle = 180 - 30 - 40

180 - 30 = 150

150 - 40 = 110

so the missing angle = 110

5 0

3 years ago

George cut a cake into eight pieces. Explain what the unit fraction of the cake is.

morpeh [17]

Answer:

1/8th

Step-by-step explanation: A unit fraction is a rational number written as a fraction where the numerator is one and the denominator is a positive integer. A unit fraction is therefore the reciprocal of a positive integer, 1/n. Examples are 1/1, 1/2, 1/3, 1/4 ,1/5, etc. so in this case the cake is eight slices so 1/8

6 0

3 years ago

Ben and Josh went to the roof of their 40-foot tall high school to throw their math books offthe edge.The initial velocity of Be

Taya2010 [7]

Answer

Josh's textbook reached the ground first

Josh's textbook reached the ground first by a difference of $t=0.6482$

Step-by-step explanation:

Before we proceed let us re write correctly the height equation which in correct form reads:

$h(t)=-16t^2 +v_{o}t+s$ Eqn(1).

Where:

$h(t)$ : is the height range as a function of time

$v_{o}$ : is the initial velocity

$s$ : is the initial heightin feet and is given as 40 feet, thus Eqn(1). becomes:

$h(t)=-16t^2 + v_{o}t + 40$ Eqn(2).

Now let us use the given information and set up our equations for Ben and Josh.

Ben:

We know that $v_{o}=60ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+60t+40$ Eqn.(3)

Josh:

We know that $v_{o}=48ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+48t+40$ Eqn. (4).

Now since we want to find whose textbook reaches the ground first and by how many seconds we need to solve each equation (i.e. Eqns. (3) and (4)) at $h(t)=0$ . Now since both are quadratic equations we will solve one showing the full method which can be repeated for the other one.

Thus we have for Ben, Eqn. (3) gives:

$h(t)=0-16t^2+60t+40=0$

Using the quadratic expression to find the roots of the quadratic we have:

$t_{1,2}=\frac{-b+/-\sqrt{b^2-4ac} }{2a} \\t_{1,2}=\frac{-60+/-\sqrt{60^2-4(-16)(40)} }{2(-16)} \\t_{1,2}=\frac{-60+/-\sqrt{6160} }{-32} \\t_{1,2}=\frac{15+/-\sqrt{385} }{8}\\\\t_{1}=4.3276 sec\\t_{2}=-0.5776 sec$