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luda_lava [24]
3 years ago
11

The equation represents the area, A, of a rectangle, in square units.

Mathematics
1 answer:
dimulka [17.4K]3 years ago
4 0

Look up "Everything You Need To Know About Math In One Big Fat Notebook pdf." It's the best thing I've ever been given, I have it with me in math class all the time and I've aced every test.

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Bryce tried to solve an equation step by step.
Aloiza [94]

$c=\frac{1}{3}

Solution:

Given equation is \frac{8}{3}=3c+\frac{5}{3}.

To solve the equation by step by step.

Step 1: Given

$\frac{8}{3}=3c+\frac{5}{3}$

Step 2: Combine like terms together.

Plus symbol changed to minus when the term goes from right to left (or) left to right of the equal sign.

$\frac{8}{3}-\frac{5}{3}=3c$

Step 3: Subtract the fractions in the left side.

$\frac{3}{3}=3c$

⇒ 1=3c$

Step 4: Divide both side of the equation by 3, we get

$\frac{1}{3} =\frac{3c}{3}$

$\frac{1}{3} =c$

Hence, the answer is c=\frac{1}{3}.

8 0
4 years ago
Read 2 more answers
Can someone give me the answer
Alex Ar [27]

Answer:

C

Step-by-step explanation:

The T shape is composed of 2 rectangles.

Area of top rectangle = 20 × 4 = 80 cm²

Area of upright triangle = 16 × 6 = 96 cm²

Total area = 80 + 96 = 176 cm² → C

6 0
3 years ago
If I have 7 and one eight and have to covert every 6 into a dollar then whats my answer
KatRina [158]
7 1/8 = 57/8
57 divide by 6= 9.5
So you would have 9 1/2
5 0
3 years ago
F(x) = 3x - 2<br><br> f(x) = 0, x=?
podryga [215]

Answer:

2/3 =x

Step-by-step explanation:

f(x) = 3x - 2

Let f(x) =0

0 = 3x-2

Add 2 to each side

2 = 3x-2+2

2 =3x

Divide by 3

2/3 =3x/3

2/3 =x

8 0
3 years ago
Read 2 more answers
Determine whether the functions y 1 and y 2 are linearly dependent on the interval​ (0,1). y 1equals2 cosine squared t minus 1​,
Fudgin [204]

Answer:

D. Since y₁ is not a constant multiple of y₂ on​ (0,1), the functions are linearly independent on​ (0,1).

Step-by-step explanation:

y₁=2Cos²t-1

y₂=6Cos2t

We want to determine if y₁ and y₂ are linearly independent in the interval (0,1).

To do this, we show that there does not exist any c₁ and c₂ in (0,1) that makes the expression:

f(t)=c₁(2Cos²t-1)+c₂6Cos2t=0.

If c₁ and c₂=0

f(t)=0

Let c₁=1 and c₂=-⅓

f(t)=c₁(2Cos²t-1)+c₂6Cos2t

=2Cos²t-1-⅓*6(cos²t-sin²t)

=2Cos²t-1-2cos²t+2sin²t

=2sin²t-1

Since f(t)≠0, y₁ is not a constant multiple of y₂ and the functions are linearly independent on (0,1).

8 0
3 years ago
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