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netineya [11]
2 years ago
9

What is the value of a3 in the sequence? 2, 5, 10, 17,. 2 5 10 17.

Mathematics
1 answer:
Bess [88]2 years ago
3 0
The answer to your mathematical question is 5
You might be interested in
Find the measure of the indicated arcs or central angles in OA. DG is a diameter.
lara31 [8.8K]

Answer:

Arc DE = 90°

m<GAB = 82°

Arc DC = 49°

Step-by-step explanation:

Given:

m<EAF = 74°

m<EAD = right angle = 90°

Arc BG = 82°

Required:

Arc DE,

<GAB, and

Arc DC

Solution:

Recall that the central angle measure = the intercepted arc measure.

Therefore:

✔️Arc DE = m<EAD

Arc DE = 90° (Substitution)

✔️m<GAB = arc BG

m<GAB = 82° (Substitution)

✔️Arc DC = m<CAD

Find m<CAD

m<CAD = ½(180 - m<GAB)

m<CAD = ½(180 - 82)

m<CAD = 49°

Arc DC = m<CAD

Arc DC = 49°

6 0
2 years ago
You can do both problems if want
Agata [3.3K]
A= π r2 and v=3.14d

---Volume(v=3.14d):

3.14(15) equals 47.1

47.1 rounds to 47

nearest hundreth would be 0 that rounds to .1 or .10,which rounds to 47
v=47

---Area(π r2)

3.14(7.5)^2 is 3.14(56.25)
176.625

176.625 rounded to the nearest hundreth is 176.630.

Answer:

The area of a circle with the diameter of 15 is 176.630.
4 0
3 years ago
How do I solve this problem?
Paraphin [41]

Answer:

4

Step-by-step explanation:

17-5=12/3=4 so yeah that is all you need to know

4 0
3 years ago
Read 2 more answers
Find the area of the shaded region
AlexFokin [52]

Answer:

7\pi cm²

Step-by-step explanation:

First, find the area of the big circle with the formula A = \pir²

A = \pi(3)²

A = 9\pi

Now, we can find the areas of the smaller circles. Since they have the same radius, they are congruent (will have the same area)

A = \pir²

A = \pi(1)²

A = \pi

Now, we will subtract the areas of the smaller circles from the area of the big circle to find the area of the shaded region:

9\pi - \pi - \pi = 7\pi

So, the area of the shaded region is 7\pi cm²

5 0
3 years ago
A fair dice is thrown what is the probability that a 6 4or 5 is thrown​
antiseptic1488 [7]

There is a 3/6 or 1/2 chance that a 6, 4, or 5 is thrown. This is because a fair dice has as 6 sides, therefore, as three numbers were listed, there is a 3/6 probability that 6, 4 or 5 will be thrown.

4 0
3 years ago
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