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Leto [7]
3 years ago
15

PLEASE ANSWER ASAP

Mathematics
2 answers:
Anton [14]3 years ago
7 0

Answer:

19 roses

Step-by-step explanation:

Say 1st yard = x and 2nd yard = y

Our system is:

x = y - 10

x + 9 = 2((y - 10) - 9)

We can use substitution: y - 10 + 9 = 2y - 20 - 18

-> y - 19 = 2y - 38 -> 19 = y

Taya2010 [7]3 years ago
4 0

I would say, well I THINK It's 2

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Fred and Frank play a game. Fred picks an even number X and asks Frank to add all even numbers between 0 and X (inclusive) as fa
TiliK225 [7]

Answer:

The even numbers between 0 and X represents an arithmetic sequence with a common difference of 2

The rule of arithmetic sequence = a + d(n - 1)

Where a is the first term and n is the number of terms

So, for the even numbers between 0 and X

The first term = a = 0

d = 2

So, we need to find n at the last term which is X

∴ X = 0 + 2 ( n -1 )

∴ n - 1 = X/2

∴ n = X/2 + 1

The sum of the arithmetic sequence = (n/2) × (2a + (n−1)d)

Substitute with a and d and X

So, the sum = (n/2) * (2*0 + (n−1)*2)

                   = (n/2) * ((n−1)*2)

                   = n(n-1)

                   = (X/2 + 1) * (X/2)

                   = X/2 by (X/2 + 1)

So, The quick way to add all even numbers between 0 and X always works.

8 0
4 years ago
What name would I give this shape
masha68 [24]
It is a quadrilateral because it has four sides. 
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3 0
4 years ago
Write 10,100,or 1,000 to make each statement true. A. 1,000,000 is--------------- times greater than 10,000.
VashaNatasha [74]

Answer:100

Step-by-step explanation: 10 x 10000 = 100000 x 10 = 1000000. If we multiply 100 x 10000, we got 1 million

4 0
3 years ago
Can some one explain to me wht to do plz!!!
mestny [16]
If you like my answer, please make me the brainliest answer! It means a lot. :)

They've told us the net force already, which is 25 N.

We use this to calculate the unknown force from the right side.

All we do is 135 - 25 = 110 N!
6 0
4 years ago
See attached photo please!
mariarad [96]
Hmm I'm not really sure/ really lazy to do this I just need to answer a question to ask mine so yeah!
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3 years ago
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