Admitting that the "a" is a capital A for normal pigmentation and "d" is a capital D for dimpled chin, meaning that these are the dominant traits, the fraction expected to be albino with a non-dimpled chin is of 1/16.
When two heterozygous are crossed and two characteristics are being analysed, the offspring quantity that will possess the two recessive traits can be represented by 1/16. This is easily confirmed when a Punnett square is made. Considering that both parents were heterozygous, on both sides of the crossing in the Punnett square, you would have the following alleles' combination: AD, Ad, aD, and ad. The offspring that would be homozygous recessive (aadd) would correspond to only 1/16.
The choice is C i just took that quiz
I hope this helps!!!
Answer:
<h2>
Interphase : divided into three phases, i) G1 phase, ii) S phase and iii) G2 phase.</h2><h2>Mitotic phase: i) prophase, ii) metaphase, iii) anaphase and v) telophase.</h2>
Explanation:
interphase : divided into three phases, i) G1 phase, ii) S phase and iii) G2 phase.
G1 phase: cell decide whether to divide or not and prepare itself for replication of DNA and arrange replication machinery. otherwise it goes to G 0 phase.
S phase: DNA replication occurs in this phase.
G2 phase: cell duplicates all their contents and prepares for mitotic phase.
Mitotic phase:
i) prophase- chromosome condensation occurs,
ii) metaphase - chromosome arranges in meta-plate and spindle binds to each chromosomes at centromere.
iii) anaphase- chromosome separates from sister chromatids.
iv) telophase- chromosome moves to each ends and formation of nuclear membrane begins.
cytokinesis: there is division of cytoplasm and forming two daughter cells.
