Answer:
103
Step-by-step explanation:
appears to be an arithmetic sequence question where sequence is 7, 13, 19 meaning the initial value is 7 and the common difference is 6 so we'll plug into this formula:
= 7 + (17 - 1) · 6
= 7 + (16 · 6)
= 7 + 96
'7' because that's the initial value
'6' because that the common difference
'17' because that's the position the question is asking
Answer:
X = 119, Y = 61, Z = 119
Step-by-step explanation:
These are supplementary angles and equal 180.
180 - 61 = 119
Opposite angles are congruent
Answer:
0.333333333
Step-by-step explanation:
0.333333333×0.3=1
3/10=0.3
The median, because the data is not symmetric and there are outliers is the data is not symmetric and there are outliers.
The median of the data set is 8 cakes, while the average is 7.5.
However, 21 of the 31 chefs, or roughly 2/3, made 8 or more cakes. This makes the median a better center for this data, since the data is clearly skewed. The four chefs that made 1 cake each brings the average down, skewing the mean and making the median a better representation of the data.
Answer:
![m \times H=\left[\begin{array}{c c c}\boxed{-9} & \boxed{36} & \boxed{-\dfrac{9}{2}}\end{array}\right]](https://tex.z-dn.net/?f=m%20%5Ctimes%20H%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%20c%20c%7D%5Cboxed%7B-9%7D%20%26%20%5Cboxed%7B36%7D%20%26%20%5Cboxed%7B-%5Cdfrac%7B9%7D%7B2%7D%7D%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
<u>Calculate the value of m</u>
Given:
![3\left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]=\dfrac{2}{3}m \times \left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]](https://tex.z-dn.net/?f=3%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%20c%7D-1%20%26%202%20%5C%5C4%20%26%208%5Cend%7Barray%7D%5Cright%5D%3D%5Cdfrac%7B2%7D%7B3%7Dm%20%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%20c%7D-1%20%26%202%20%5C%5C4%20%26%208%5Cend%7Barray%7D%5Cright%5D)
Therefore:



<u>Calculate the value of H</u>
Given:
![\left(H+ \left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]\right)+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]=\left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]+\left(\left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]\right)](https://tex.z-dn.net/?f=%5Cleft%28H%2B%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%20c%20c%7D1%20%26%204%20%26%20-2%5Cend%7Barray%7D%5Cright%5D%5Cright%29%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%20c%20c%7D3%20%26%202%20%26%20-6%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%20c%20c%7D-2%20%26%208%20%26%20-1%5Cend%7Barray%7D%5Cright%5D%2B%5Cleft%28%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%20c%20c%7D1%20%26%204%20%26%20-2%5Cend%7Barray%7D%5Cright%5D%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%20c%20c%7D3%20%26%202%20%26%20-6%5Cend%7Barray%7D%5Cright%5D%5Cright%29)
Therefore:
![\implies H= \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]](https://tex.z-dn.net/?f=%5Cimplies%20H%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%20c%20c%7D-2%20%26%208%20%26%20-1%5Cend%7Barray%7D%5Cright%5D)
<u />
<u>Calculating m × H</u>
<u />
<u />![\implies m \times H=\dfrac{9}{2} \times \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]](https://tex.z-dn.net/?f=%5Cimplies%20m%20%5Ctimes%20H%3D%5Cdfrac%7B9%7D%7B2%7D%20%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%20c%20c%7D-2%20%26%208%20%26%20-1%5Cend%7Barray%7D%5Cright%5D)
<u />![\implies m \times H=\left[\begin{array}{c c c}\dfrac{9}{2}(-2) & \dfrac{9}{2}(8) & \dfrac{9}{2}(-1)\end{array}\right]](https://tex.z-dn.net/?f=%5Cimplies%20m%20%5Ctimes%20H%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%20c%20c%7D%5Cdfrac%7B9%7D%7B2%7D%28-2%29%20%26%20%5Cdfrac%7B9%7D%7B2%7D%288%29%20%26%20%5Cdfrac%7B9%7D%7B2%7D%28-1%29%5Cend%7Barray%7D%5Cright%5D)
<u />