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3 years ago

Lines QS and NR intersect at P. Ray PM is perpendicular to line SQ. What is the value of y?

Mathematics

1 answer:

Anastaziya [24]3 years ago

3 0

Answer:

A. 13

Step-by-step explanation:

$(6y - 14) + 90 + (2y) = 180$ (angles on a straight line)

Solve for y

$6y - 14 + 90 + 2y = 180$

Collect like terms

$6y + 2y - 14 + 90 = 180$

$8y + 76 = 180$

Subtract 76 to both sides

$8y + 76 - 76 = 180 - 76$

$8y = 104$

Divide both sides by 8

$\frac{8y}{8} = \frac{104}{8}$

$y = 13$

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What is the equation of the circle with radius, r = 11 , and the center at (0, - 7)

Dimas [21]

Answer:

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Given (h, k) = (0, - 7) and r = 11, then

(x - 0)² + (y - (- 7))² = 11², that is

x² + (y + 7)² = 121 → A

4 0

3 years ago

What are the amplitude and midline?

Vadim26 [7]

Answer:

Amplitude 3; midline y=2

Step-by-step explanation:

The midline is the mean of both ends of the function in the graph.

$\frac{5-1}{2}=2$

The amplitude is the vertical distance between the midline and one of the end points.

$5-2=3$

(sorry for the basic math, i just want to make sure you know where im getting the values from)

7 0

3 years ago

The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati

makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

$y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\$

And the second one would be

$y = 2-x \,\,\,\,\,, 1 \leq x \leq 2$ .

If you rotate the first region around the "y" axis you get that

$A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51$

And if you rotate the second region around the "y" axis you get that

$A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188$

And the sum would be 2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first region around the x axis you get that

$A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708$

And if you rotate the second region around the x axis you get that

$A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472$

And the sum would be 1.5708+1.0472 = 2.618

7 0

4 years ago

419.10 419.099 greater than equal too or less than

Veronika [31]

419.10>419.099 419.10 is greater than 419.009

4 0

3 years ago

Someone please help me

KonstantinChe [14]

Your answer is correct

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3 years ago