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Tju [1.3M]
3 years ago
6

2. The line that passes through the points (-6, p)

Mathematics
1 answer:
Kobotan [32]3 years ago
5 0
Answer: -26=p


Explanation: The slope formula is m=(y2-y1)/(x2-x1).

Thus, we have 6=(2-p)/(-10-(-6)).

Combining the xs gives us 6=(2-p)/-4.

Multiplying both sides by -4 leaves us with -24=2-p.

We do -24-2 to isolate p and find that p=-26.
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Draw two segments. How many common points is it possible for the segments to have? Explore all possibilities.
Arte-miy333 [17]

A segment is bounded by two endpoints.

The two segments can have up to two common points

Assume the line segments are AB and CD where the length of AB is greater than the length of CD.

<u>The possibilities are:</u>

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Multiply (a-b)(a^2+ab+b^2)​
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=(a-b)(a^2+ab+b^2)

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Hello! I'm having a really hard time solving this by Elimination and could really use some help ​
Mamont248 [21]

Answer:

x= 3, y=0, z= 1

Step-by-step explanation:

Let's label the 3 given equations first.

2x +3y +4z= 10 -----(1)

3x +2y -4z= 5 -----(2)

x +4y +2z= 5 -----(3)

(1) +(2):

<em>This</em><em> </em><em>is</em><em> </em><em>to</em><em> </em><em>eliminate</em><em> </em><em>the</em><em> </em><em>z</em><em> </em><em>term</em><em>.</em>

2x +3y +4z +3x +2y -4z= 10 +5

5x +5y= 15

<em>Divide</em><em> </em><em>by</em><em> </em><em>5</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>:</em>

x +y= 3 -----(4)

(3) ×2:

2x +8y +4z= 10 -----(5)

(2) +(5):

<em>This</em><em> </em><em>is</em><em> </em><em>to</em><em> </em><em>eliminate</em><em> </em><em>z</em><em> </em><em>term</em><em>.</em>

3x +2y -4z + 2x +8y +4z= 5 +10

5x +10y= 15

<em>Divide</em><em> </em><em>by</em><em> </em><em>5</em><em> </em><em>throughout</em><em>.</em>

x +2y= 3 -----(6)

(6) -(4):

x +2y -(x +y)= 3 -3

x +2y -x -y= 0

y= 0

subst. y=0 into (4):

x +0= 3

x= 3

subst. x=3, y=0 into (3):

3 +4(0) +2z= 5

3 +2z= 5

2z= 5 -3

2z= 2

z= 2÷2

z= 1

6 0
3 years ago
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