Question

A pitched ball is hit by a batter at a 45° angle and just clears the outfield fence, 107 m away. If the fence is at the same height as the pitch, find the velocity of the ball when it left the bat. Ignore air resistance.

Answer 1

Answer:

31 m/s

Explanation:

Answer 2

Answer:

31 m/s

Explanation:

$R=\frac{v^2i sin(20)}{g}$

$98=\frac{v^2i sin(2)*(45))}{9.80}$

$98=\frac{v^2i sin (90)}{9.80}$

$98=\frac{v^2i}{9.80}$

$ui=31 m/s$