3 hours I think?
There’s not enough context for this.
It can rlly be anything
0.65625 is the decimal product of the fractions 3/4 & 7/8 whereas 7/8 can be simplified to 0.875 in decimal form... comparing both the values, we see that 7/8 is greater than the product of 3/4 and 7/8.
Answer:
Kay's husband drove at a speed of 50 mph
Step-by-step explanation:
This is a problem of simple motion.
First of all we must calculate how far Kay traveled to her job, and then estimate the speed with which her husband traveled later.
d=vt
v=45 mph
t= 20 minutes/60 min/hour = 0.333 h (to be consistent with the units)
d= 45mph*0.333h= 15 miles
If Kay took 20 minutes to get to work and her husband left home two minutes after her and they both arrived at the same time, it means he took 18 minutes to travel the same distance.
To calculate the speed with which Kate's husband made the tour, we will use the same initial formula and isolate the value of "V"
d=vt; so
v=
d= 15 miles
t= 18 minutes/60 min/hour = 0.30 h (to be consistent with the units)
v=
Kay's husband drove at a speed of 50 mph
Answer:
Step-by-step explanation:
The lower value is 15,The upper value is 100, The median is 32 and 39, The lower quartile is 30, the upper quartile is 50, and the interquartile range is 36.