Actually the position function with respect to time under constant acceleration is:
a=g
v=⌠g dt
v=gt+vi
s=⌠v
s=gt^2/2+vit+si
So if vi and si are zero then you just have:
s=gt^2/2
Notice that it is not gt^2 but (g/2) t^2
So the first term in any quadratic is half of the acceleration times time squared because of how the integration works out...
Anyway....
sf=(a/2)t^2+vit+si
(sf-si)-vit=a(t^2)/2
2(sf-si)-2vit=at^2
a=(2(sf-si)-2vit)/t^2 and if si and vi equal zero
a=(2s)/t^2
Answer:
<u><em>-11</em></u>
Step-by-step explanation:
4+(-15)=
<u><em>-11</em></u>
Answer:
B and E
Step-by-step explanation:
Subtract the area of the rug from the bedroom floor.
<span>Since he was 30 flower pots and puts 10 in each, you would need to multiply 30 by 10 which leads to 300 seeds.</span>
85986 7/43 using kcf it becomes 14788588/86 times 1/2(flipped)
