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scoundrel [369]
2 years ago
5

The wholesale price for a dozen pairs of socks is $4.30. The retail price for the same dozen pairs of socks is $9.25. What is th

e mark-up the retailer used? Write your answer as a complete sentence.
Mathematics
1 answer:
Mandarinka [93]2 years ago
5 0

Answer:

the mark up used by the retailer is 115.12% of the wholesale price

Step-by-step explanation:

Mark-up is the percentage increase of the retail price over the wholesale price

Mark-up = (difference between retail and whole sale price / retail price ) x 100

difference between retail and whole sale price = $9.25 - $4.30 = $4.95

(4.95 / 4.3) x 100 = 115.12%.

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Paladinen [302]
It's a cube so x should also equal 6
4 0
3 years ago
Can someone answer this please with an explanation.
Harrizon [31]

Answer:

x=92

Step-by-step explanation:

those to angles are supplementary meaning that they add up to equal 180

so you set up the equation 180=x+x-4

180=2x-4

step 1 add 4 to each side

184=2x

step 2 divide each side by 2

x=92

so the angles equal 92 and 88

5 0
3 years ago
Read 2 more answers
K(x) = 2x – 4; Find k (x + 4)
Iteru [2.4K]

Answer:

k=  −2x−16 /x

Step-by-step explanation:

5 0
2 years ago
Because of the rainy season, the depth in a pond increases 3% each week. Before the rainy season started, the pond was 10 feet d
Dafna11 [192]

It's not perfectly clear, but you seem to be saying that each week, the
pond becomes 3% deeper than it was THE PREVIOUS WEEK.

If I'm reading that correctly, then the pond is 10-ft deep when the rainy
season begins, and after 'x' weeks later, the depth is

                     D = 10 (1.03)^x            feet.

After 8 weeks, the depth is        D = 10 (1.03)⁸  =  12.67 feet .

                         rounded to the nearest foot,  D = 13 ft.

                

7 0
3 years ago
Read 2 more answers
The height of a punted football can be modeled with the quadratic function 0.01x^2 + 1.18x+2.
Fantom [35]

The function of the path of the punted ball is a quadratic function which

follows the path of a parabola.

The correct responses are;

Part A: The coordinates of the vertex is \underline {(59, \, 36.81)}

Part B: The maximum height of the punt is <u>36.81 ft.</u>

Part C: The defensive player must reach up to <u>7.65 feet</u> to block the punt.

Part D: The distance down the field the ball will go without being blocked is approximately <u>119.67 ft.</u>

<u />

Reasons:

The function for the height of the punted ball is; h = -0.01·x² + 1.18·x + 2

Assumption; The distances are feet.

Part A: By completing the square, we have;

f(x) = -0.01·x² + 1.18·x + 2

100·f(x) = -x² + 118·x  + 200

-100·f(x) = x² - 118·x  - 200

x² - 118·x + (118/2)²= 200 + (118/2)²

(x - 59)² = 200 + (59)² = 3681

(x - 59)² - 3681

At the vertex, -3281 = -100·f(x)

∴ f(x) at the vertex = -3681/-100 = 36.81

\mathrm{\underline{Coordinate \ of \ the \ vertex = (59, \, 36.81)}}

Part B: The maximum height is given by the y-value at the vertex = 36.81 ft.

Part C: When <em>x</em> = 5, we have;

h = -0.01·x² + 1.18·x + 2

h = -0.01 × 5² + 1.18 × 5 + 2 = 7.65

The defensive player must reach up to 7.65 feet to block the punt

Part D: The distance the ball will go before it hits the ground is given by

the function, for the height as follows;

h = -0.01·x² + 1.18·x + 2 = 0

From the completing the square method, above, we get;

-0.01·x² + 1.18·x + 2 = 0

x² - 118·x  - 200 = 0

x² - 118·x + (118/2)²= 200 + (118/2)²

x² - 118·x + (59)²= 200 + (59)² = 3681

(x - 59)² = 3681

x - 59 = ±√3681

x = 59 ± √3681

x = 59 + √3681 ≈ 119.67

The distance down the field the ball will go without being blocked, x ≈ <u>119.67 ft.</u>

<u />

Learn more here:

brainly.com/question/24136952

5 0
2 years ago
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