Time each dog spent sleeping during each of two conditions
There are a number of ways this can be done. One that is fairly simple is as follows.
Triangle ABC has base AC = 9 and height B to AC of 3 (found by counting squares). Thus its area is ∆ABC = (1/2)·9·3 = 13.5 square units.
Triangle ACF has base AC = 9 and height F to AC of 3, so will have the same area as triangle ABC, 13.5 square units.
Trapezoid CDEF has base CD of 6, base EF of 4 and height EF to CD of 6 (found by counting squares). Thus its area is CDEF = (1/2)(6 + 4)(6) = 30.
The total area of the entire figure is then
... ∆ABC + ∆ACF + CDEF = 13.5 + 13.5 + 30 = 57 square units.
Answer:
122°
Step-by-step explanation:
The formula for finding the sum of all angles in a polygon is:
(n-2) * 180°
n is the number of angles
Here n = 7, so the sum of all angles is
(7-2) * 180° = 900°
x = 900 - 128 - 130 - 120 - 115 - 145 - 140 = 122°
Make me the brainliest ;)
1) ab+c=d subtract c on both sides
ab=d-c divide b on both sides
a=d/a - c/a or a=(d-c)/d
