59,468
9 is in the thousands place
If you want to round, look at the hundreds place value. It is a 4. Because 4 is less than 5, round down.
59,000 is your rounded
hope this helps
Step-by-step explanation:
- A(2,4)=A'(-4,-2)
- B(-3,-5)=B'(5,3)
- C(2,-3)=C'(3,-2)
- D(-4,9)=D'(-9,4)
- E(10,4)=E'(-4,-10)
- F(-1,-7)=F'(7,1)
- G(-4,8)=G'(-8,4)
- H(-4,-5)=H'(5,4)
- J(-7,-2)=J'(2,7)
- K(0,9)=K'(-9,0)
- L(0,-3)=L'(3,0)
- M(-5,0)=M'(0,5)
- l(1,-8)=l'(8,-1)
- N(2,0)=N'(0,-2)
<h2>stay safe healthy and happy.</h2>
Begin by finding the lowest point the quadratic equation can be, the vertex;
x²-1= is just a translation down of the graph x²
vertex; (0, -1) and since the graph of x² would extend to infinity beyond that point, we can say {x| x≥0} for domain and {y| y≥-1}.
For the linear equation, it is possible to have all x and y values, therefore range and domain belong to all real numbers.
Hope I helped :)
Answer:
A sample size of at least 737 specimens is required.
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find the width M as such

In which
is the standard deviation of the population and n is the size of the sample.
In this problem, we have that:

So:





A sample size of at least 737 specimens is required.
The temperature on Tuesday afternoon is below 38 degrees Fahrenheit. As it states in the question the temperature on Tuesday morning was 27 degrees Fahrenheit and rose 10 more degrees at noon. Which makes is 37 degrees Fahrenheit at noon on Tuesday. You get this by taking 27 degrees and adding 10 degrees.