Answer:
ASA and AAS
Step-by-step explanation:
We do not know if these are right triangles; therefore we cannot use HL to prove congruence.
We do not have 2 or 3 sides marked congruent; therefore we cannot use SSS or SAS to prove congruence.
We are given that EF is parallel to HJ. This makes EJ a transversal. This also means that ∠HJG and ∠GEF are alternate interior angles and are therefore congruent. We also know that ∠EGF and ∠HGJ are vertical angles and are congruent. This gives us two angles and a non-included side, which is the AAS congruence theorem.
Since EF and HJ are parallel and EJ is a transversal, ∠JHG and ∠EFG are alternate interior angles and are congruent. Again we have that ∠EGF and ∠HGJ are vertical angles and are congruent; this gives us two angles and an included side, which is the ASA congruence theorem.
Separate into two groups
y^3(5y+4) + 5(5y+4)
(y^3 + 5)(5y + 4)
Answer:
Please English translate this for my help
Step-by-step explanation:
(4^9)5 X 4^0
4^9 is 262,144 x 5 = 1,310,720
1,310,720 x 1 = 1,310,720
y = 8
using the ' gradient formula' m = (y₂ - y₁)/(x₂ - x₁)
with (x₁, y₁) = (3, 3), (x₂, y₂) = (- 5, y) and m = - 
(y - 3)/( - 5 - 3) = -
(y - 3)/(-8) = -
multiply both sides by - 8 to eliminate fractions
y - 3 = 5
add 3 to both sides
y = 5 + 3 =8
