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loris [4]
2 years ago
9

Find the length of Radius?

Mathematics
1 answer:
zloy xaker [14]2 years ago
7 0

Answer:

0.5

Step-by-step explanation:

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Which of the following expressions are equivalent to 3V 2 ? Select all that apply. ​
allsm [11]

Answer:   A  C and D

                               

Step-by-step explanation:

3 0
2 years ago
The space inside a circle is the ___ of the circle. circumference <br>diameter<br>area<br>radius ​
Phantasy [73]
Area is the inside of the circle
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3 years ago
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Make a conjecture about the next item in the sequence 1, -4, 9, -16
Snezhnost [94]
To get -4 from 1, we must either subtract 5 from 1 or mult. 1 by -4.  Unfortunately subtracting 5 from -4 does not result in 9, and mult -4 by -4 does not result in -16.  So neither "works"  in predicting the next term.

Can you think of any other experiments to do that would help you discover the pattern 1, -4, 9, -16?  


4 0
3 years ago
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Use any of the methods to determine whether the series converges or diverges. Give reasons for your answer.
Aleks [24]

Answer:

It means \sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6} also converges.

Step-by-step explanation:

The actual Series is::

\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}

The method we are going to use is comparison method:

According to comparison method, we have:

\sum_{n=1}^{inf}a_n\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n

If series one converges, the second converges and if second diverges series, one diverges

Now Simplify the given series:

Taking"n^2"common from numerator and "n^6"from denominator.

=\frac{n^2[7-\frac{4}{n}+\frac{3}{n^2}]}{n^6[\frac{12}{n^6}+2]} \\\\=\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{n^4[\frac{12}{n^6}+2]}

\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n=\sum_{n=1}^{inf} \frac{1}{n^4}

Now:

\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\ \\\lim_{n \to \infty} a_n = \lim_{n \to \infty}  \frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\=\frac{7-\frac{4}{inf}+\frac{3}{inf}}{\frac{12}{inf}+2}\\\\=\frac{7}{2}

So a_n is finite, so it converges.

Similarly b_n converges according to p-test.

P-test:

General form:

\sum_{n=1}^{inf}\frac{1}{n^p}

if p>1 then series converges. In oue case we have:

\sum_{n=1}^{inf}b_n=\frac{1}{n^4}

p=4 >1, so b_n also converges.

According to comparison test if both series converges, the final series also converges.

It means \sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6} also converges.

5 0
3 years ago
2. Rosa and her friends went kayaking at a local lake. Rosa paid $12 for
Alinara [238K]

Answer:

THREE HOURS

Step-by-step explanation:

34.50-12=22.5

22.5/7.50=

=3

5 0
3 years ago
Read 2 more answers
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