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Mandarinka [93]
2 years ago
14

A certain television is advertised as a 85 inch TV if the width of the TV is 67 how tall is the TV

Mathematics
2 answers:
GaryK [48]2 years ago
6 0

Answer:

Step-by-step explanation:

Apply the Pythagorean Theorem:

85^2 = 67^2 + h^2, where h is the height of the TV

Then 7225 = 4489 + h^2, or

h^2 = 2736, or h = +√2736 = 52.3 inches

Lunna [17]2 years ago
4 0

Answer:

I believe the answer is 12

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9 Cars washing in 4 hours
4 0
3 years ago
Mr.jeff divided his money in the ratio 4:2 between Jon and jack Jon got the smaller amount of $1,256 how much did jack get?
nadezda [96]
Ratio in which Mr.Jeff divided his money between Jack and Jon = 4:2
Let us assume the common ration to be = x
The amount of money that Jon got = $1256
Then
2x = 1256
x = 1256/2
   = 628
Then
The amount of money that Jon got = 4 * 628 dollars
                                                         = 2512 dollars
So the amount that Jack got is $2512. As Jack got the major or the bigger share of the money, so the answer is correct. I hope the procedure for solving the question is also easy for you to understand.
6 0
3 years ago
What is the length of the diagonal of the triangle?
Setler79 [48]

Answer:

21.25

Step-by-step explanation:

use the Pythagorean theorem, it is given that the shape is a rectangle so all opposite sides are congruent and all angles are right, since we know that the diagonal forms a right triangle we can use the pythagorean theorem

the Pythagorean theorm is a^2+b^2=c^2 where a and b are the legs (in this case the side of the triangle) and c is the hypotenuse which is the longest side in a right triangle

17^2+12.75^2=x^2

x^2=7225/16

now take the square root of both sides and you get -21.25 and 21.25

distance CAN NOT be negative so -21.25 isn't an option

7 0
3 years ago
A rectangle has a length of 45 inches less than 4 times its width. if the area of the rectangle is 3325 square inches, find the
Maru [420]

The length of the rectangle is based on its width, so let's call width w and put the length in terms of the width. We are told that the width is 45 less than 4 times the width, so the length is 4w - 45. Area is found by multiplying length times width and we are given the area as 3325. So we will set up length times width and solve for w, which we will then use to solve for l. 3325 = (4w - 45)(w). Multiplying out we have 3325=4w^2-45w. Move the constant over by subtraction and then we will have a quadratic that can be factored to solve for w. 4w^2-45w-3325=0. We would put that through the quadratic formula to solve for w. When we do that we get that w = 35 and w = -23.75. The 2 things in math that will never EVER be negative is time and distance/length, so -23.75 is out. That means that the width is 35. The length is 4(35) - 45 which is 95. The dimensions of your rectangle are length is 95 and width is 35. There you go!

8 0
2 years ago
Consider a population p of field mice that grows at a rate proportional to the current population, so that dp dt = rp. (note: re
krok68 [10]
This is the concept of differential equations, given that
dp/dt=rp
then:
dp/p=rdt
thus:
ln p=rt+C
p=e^(rt+C)
P=Ke^(rt)
when t=210 days=7 months, p=2k
2k=k×e^(7r)
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5 0
3 years ago
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