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3 years ago

In a grocery store, a $12 case of soda is labeled, "Get a 20% discount." What is the discount?

Mathematics

1 answer:

____ [38]3 years ago

5 0

Answer:

Sale price of the case of soda $ 9.60

Step-by-step explanation:

Sale price = $ 12 − $ 2.40 = $ 9.60

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Kelly is knitting a scarf for her brother in it to 1/3 hour to knit 3/4 foot of the scarf how fast is Kelly in knitting feet per

Naily [24]

I think the answer is 2.25 or 2 and 1/4.

You divide 3/4 by 1/3 and get 2.25 or 2 and 1/4.

I don't know if this is right, I hope it is, have a good day. c;

6 0

2 years ago

An empty bulldozer weighed 5 6/8 tons. If it scooped up 6 1/2 tons of dirt, what would be the

muminat

Answer:

12 1/4

Step-by-step explanation:

common denominator between 8 and 2 is 4, adding those up will be 12.25 in decimal form or 12 1/4

8 0

2 years ago

Which of the following will have a negative resulte<br>8- (-10)<br>12-14<br>07-(-3)

Cerrena [4.2K]

Answer:

12-14=-2 ***"""""""""""""""

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

One hundred people are surveyed and asked if they trust candidate A or candidate B or candidate C in a local election. People ar

ElenaW [278]

Answer:

5 people trust none of the candidates

Step-by-step explanation:

To know how many people surveyed trust none of the candidates we need to find:

People that trust all three candidates: 5
People that just trust candidate B and C: This is equal to people that trust candidate B and C less people that trust all three candidates. So it is equal to: 17 - 5 = 12
People that just trust candidate A and C: This is equal to people that trust candidate A and C less people that trust all three candidates. So it is equal to: 12 - 5 = 7
People that just trust candidate A and B: This is equal to people that trust candidate A and B less people that trust all three candidates. So it is equal to: 7 - 5 = 2
People that just trus candidate C: This is equal to the people that trust candidate C less people that just trust candidate B and C less people that just trust candidate A and C less people that trust all three candidates. So, it is equal to: 48 - 12 - 7 - 5 = 24
People that just trus candidate B: This is equal to the people that trust candidate B less people that just trust candidate B and C less people that just trust candidate A and B less people that trust all three candidates. So, it is equal to: 44 - 12 - 2 - 5 = 25
People that just trus candidate A: This is equal to the people that trust candidate A less people that just trust candidate A and C less people that just trust candidate A and B less people that trust all three candidates. So, it is equal to: 34 - 7 - 2 - 5 = 20

Therefore, we can calculate how many people surveyed trust at least one candidate by the sum of the previous quantities as:

5 + 12 + 7 + 2 + 24 + 25 + 20 = 95

Finally, there are 100 people surveyed and 95 people trust at least one candidate, so 5 people trust none of the candidates.

3 0

3 years ago

Read 2 more answers

The rate of change of the number of squirrels S(t) that live on the Lehman College campus is directly proportional to 30 − S(t),

pishuonlain [190]

Answer:

S(3)=22

Step-by-step explanation:

The rate of change of the number of squirrels S(t) that live on the Lehman College campus is directly proportional to 30 − S(t).

$\dfrac{dS}{dt}=k(30-S(t))\\ \dfrac{dS}{dt}+kS(t)=30k\\$The integrating factor: e^{\int k dt}=e^{kt}\\$Multiply all through by the integrating factor\\ \dfrac{dS}{dt}e^{kt}+kS(t)e^{kt}=30ke^{kt}$

$(Se^{kt})'=30ke^{kt} dt\\$Integrate both sides\\ Se^{kt}=\dfrac{30ke^{kt}}{k}+C$ (C a constant of integration)\\Se^{kt}=30e^{kt}+C\\$Divide both sides by e^{kt}\\S(t)=30+Ce^{-kt}$

When t=0, S(t)=15

$15=30+Ce^{-k*0}\\C=15-30\\C=-15$

When t = 2, S(t)=20

$20=30-15e^{-2k}\\20-30=-15e^{-2k}\\-10=-15e^{-2k}\\e^{-2k}=\dfrac23\\$Take the natural log of both sides$\\-2k=\ln \dfrac23\\k=-\dfrac{\ln(2/3)}{2}$

Therefore:

$S(t)=30-15e^{\frac{\ln(2/3)}{2}t}\\$When t=3$\\S(t)=30-15e^{\frac{\ln(2/3)}{2} \times 3}\\S(3)=21.8 \approx 22$

8 0

3 years ago