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3 years ago

PLEASE HELP!!!

Mathematics

2 answers:

Stolb23 [73]3 years ago

8 0

The answer is C 84% chance

lozanna [386]3 years ago

8 0

Answer:

Correct Answer (C)--84%

Step-by-step explanation:

Hope this helped! :)

#Platolivesmatter

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In a year group there 100 boys and 140 girls. Write as a ratio the number of boy to the number of girls. Give the answer in the

expeople1 [14]

no. of boys : no.of girls

100 : 140

to get the simplest ratio you gotta divide both with a common factor

Because both 100 and 140 share a common factor of 20

the simplest ratio will be

100/20 : 140/20

5:7

5:7 is the simplest ratio

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3 years ago

Read 2 more answers

Simplify the expression by combining like terms. 22+5m−4m+7n−8

rewona [7]

Answer: The simplified form by combining like terms is given by

$14+m+7n$

Step-by-step explanation:

Since we have given that

$22+5m-4m+7n-8$

Now, we combine the like terms :

1) First we collect m terms :

$22+5m-4m+7n-8\\\\=22+m+7n-8\\\\$

2) Combine n terms and constant terms :

$=22-8+m+7n\\\\=14+m+7n$

Hence, the simplified form by combining like terms is given by

$14+m+7n$

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3 years ago

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This year the CDC reported that 30% of adults received their flu shot. Of those adults who received their flu shot,

Vlad [161]

Using conditional probability, it is found that there is a 0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.

Conditional Probability

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this problem:

Event A: Person has the flu.

Event B: Person got the flu shot.

The percentages associated with getting the flu are:

20% of 30%(got the shot).

65% of 70%(did not get the shot).

Hence:

$P(A) = 0.2(0.3) + 0.65(0.7) = 0.515$

The probability of both having the flu and getting the shot is:

$P(A \cap B) = 0.2(0.3) = 0.06$

Hence, the conditional probability is:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.06}{0.515} = 0.1165$

0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.

To learn more about conditional probability, you can take a look at brainly.com/question/14398287

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2 years ago

A company orders 29 boxed lunches from a deli for $324.80. If each boxed lunch

UkoKoshka [18]

Answer:

Each boxed lunch costs $11.20

Step-by-step explanation:

29 boxed lunches = $324.80

divide by 29 on each one

1 boxed lunch = $11.20

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3 years ago

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Answer:

You can chose 3 in 5 :o

Step-by-step explanation:

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