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ikadub [295]
2 years ago
6

Can u help me? What is the measure of

Mathematics
2 answers:
jasenka [17]2 years ago
4 0
The answer is measure of 135
timama [110]2 years ago
3 0
The answer is 135 degrees
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Which of the following numbers must be added to complete the square in the equation below?
OLga [1]
First, take half of the coefficient of 18x then square it.

18 / 2 = 9
9^2 = 81

So, D. 81 is the answer.
4 0
3 years ago
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What number is it if you subtract 2 from a number and the new number and its absolute value are not equal?
ZanzabumX [31]
A negative number probs
6 0
3 years ago
Lia has $24. Lia and her brother together have a total of $45. The solution of the equation 24 + x = 45 is the amount of money,
Julli [10]

Answer:

21$

Step-by-step explanation:

24+x=45

-24      -24

x=21$

6 0
3 years ago
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Please explain how to solve this (<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7Ba%5E5%20b%5E3%7D%20" id="TexFormula1" ti
olchik [2.2K]
2 is the base and (\sqrt[4][a^5 b^3]) is the exponent.

the 4 is called an index and it means to fi d the fourth root of the expression under the (\sqrt[][text]) symbol.\\a fourth root is a factor that was multiplied four times. ex: 2*2*2*2=16. the fourth root of 16 is two. \\when you do square roots, you take the number representing the factor out of the radical. anything else that is not a square root stays under. ex: \\([tex]\sqrt[9][text])\\([tex]\sqrt[3*3*3][text]) there is one set of two 3's so\\([tex]3\sqrt[3][text])\\with a fourth root, you look for groups of four. the symbol of that group is placed outside the radical. anything else stays in.\\ ([tex]\sqrt[4][a^5 b^3])

(\sqrt[4][a*a*a*a*a*b*b*b]) there is one group of 4 a's so

(a\sqrt[4][a* b^3])

there really isn't anything else to do to simplify the expression
5 0
2 years ago
Find the ratio a:b, if 2a−b/6 = b/3
Tom [10]

Answer:

a:b = 2

Step-by-step explanation:

Here we need to operate with terms in order to arrive to a ratio a:b (or a/b).

We have:

2a−b/6 = b/3

Lets sum b/6 in both sides:

2a−b/6 + b/6 = b/3 + b/6

2a = b/3 + b/6

Now, we can multiply and divide b/3 by 2 to make a 6 appear on the denominator and sum it with b/6, this is, use common denominator:

2a = b/3*(2/2) + b/6

2a = 2b/6 + b/6

2a = 3b/6

2a = b/2, as 3/6 = 1/2

Now lets divide both sides by b to make an a/b appear:

2a/b = (b/2)/b

2a/b = 1/2

Finally, multiply both sides by (1/2) or divide by 2:

(2a/b)/2 = 2

a/b = 2

This is, a is twice as b. If b is 1 so a is 2; if b is 45 so a is 90, and so on.

7 0
3 years ago
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