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loris [4]
3 years ago
14

Which of the following correctly identifies who is credited with key developments of the cell theory?

Chemistry
1 answer:
vampirchik [111]3 years ago
8 0

Answer:

Matthias Schleiden, Theodor Schwann, and Rudolf Virchow

Explanation:

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Answer: amount of precipitation, average temperature

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3 years ago
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A particular reactant decomposes with a half‑life of 109 s when its initial concentration is 0.280 M. The same reactant decompos
Sophie [7]

Answer:

The order of reaction is 2.

Rate constant is 0.0328 (M s)⁻¹

Explanation:

The rate of a reaction is inversely proportional to the time taken for the reaction.

As we are decreasing the concentration of the reactant the half life is increasing.

a) For zero order reaction: the half life is directly proportional to initial concentration of reactant

b) for first order reaction: the half life is independent of the initial concentration.

c) higher order reaction: The relation between half life and rate of reaction is:

Rate = \frac{1}{k[A_{0}]^{(n-1)}}

Half life =K\frac{1}{[A_{0}]^{(n-1)} }

\frac{(halflife_{1})}{(halflife_{2})}=\frac{[A_{2}]^{(n-1)}}{[A_{1}]^{(n-1)} }

where n = order of reaction

Putting values

\frac{109}{231}=\frac{[0.132]^{(n-1)}}{[0.280]^{(n-1)}}

0.472=(0.472)^{(n-1)}

Hence n = 2

halflife=\frac{1}{k[A_{0}]}

Putting values

231=\frac{1}{K(0.132)}

K = 0.0328

4 0
3 years ago
Magnesium has a density of 1.071g/cm^3. Aluminum has a density of 2.700 g/cm^3. An unknown metal has a mass of 15g and a volume
maw [93]
To find the density you need to divide mass by volume. When you divide 15g by 14cm^3, you get a density of 1.071g/cm^3. This matches the density of magnesium, so the unknown metal is magnesium.
7 0
4 years ago
1. Metallic strontium crystallizes in a face-centered cubic lattice, with one Sr atom per lattice point. If the edge length of t
Zarrin [17]

Answer:

r=215pm

N_{Mn}=20

Explanation:

From the question we are told that:

Edge length of the unit cell l=608pm

a)

Generally the equation for The relationship between edge length and radius is mathematically given by

4r=\sqrt{2a}

Therefore

4r=\sqrt{2*608}

r=\frac{\sqrt{2*608}}{4}

r=215pm

b)

From the question we are told that:

Density \rho=7.297

Edge length of l=630.0 pm=>630*10^-{10}

Therefore Volume  is given as

V=l^3

V=630*10^-{10}^3

V=2.50047*10^{−22}

Generally the equation for Mass is mathematically given by

m=Volume*density

m=V*\rho

m=2.50047*10^{−22}*7.297

m=1.83*10^{-21}g

Therefore Molarity is given as

n=\frac{M}{Molar M}

n=\frac{1.83*10^{-21}g}{55}

n=3.32*10^{-23}

Finally The atoms in a unit cell is

N_{Mn}=Moles*Avogadro\ constant

N_{Mn}=3.32*10^{-23}*6.023*10^{23}

N_{Mn}=20

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