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2 years ago

Antara berikut ciri manakah bear tentang cuka?

Chemistry

2 answers:

Tasya [4]2 years ago

6 0

C, because vinegar ph scale is 2.5

allsm [11]2 years ago

3 0

Answer:

c. nilai pH kurang dari 7

Explanation:

cuka adalah acid

nilai pH bagi acid adalah

antara 1 hingga 6

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The nucleus’ pull on its electrons, taking into account any attractions weakened by shielding is called the:

Sever21 [200]

Answer:

It's called the shielding effect

Explanation:

It describes the decrease in attraction between an electron and the nucleus in any atom with more than one electron shell. (I hope this helps)

8 0

2 years ago

Calculate the average rate of decomposition of NH4NO2 by the reaction 2NH4O5(aq) --> N2(g) H2O(g) at the following time inter

igor_vitrenko [27]

Answer:

$r=-0.033\frac{M}{s}$

Explanation:

Hello!

In this case, since the average rate of reaction is computed as a change given by:

$r=\frac{\Delta [NH_4NO_2 ]}{\Delta t}$

In such a way, given the concentrations at the specified times, we plug them in to obtain:

$r=\frac{(1.48M-4.12M)}{(330s-250s)}\\\\r=-0.033\frac{M}{s}$

Whose negative sign means the concentration decreased due to the decomposition.

Best regards!

6 0

2 years ago

What are metalloids?

goldenfox [79]

A metalloid is a type of chemical element which has a preponderance of properties in between, or that are a mixture of, those of metals and nonmetals.

3 0

2 years ago

Read 2 more answers

How many moles of carbon are there in a 0.70 g (3.5 carat) diamond?

maksim [4K]

Answer:

3.5 x 10^22 moles of carbon are there in a 0.70 g (3.5 carat) diamond.

Explanation:

In case of diamond, the number of atoms is the same as the number of molecules.

7 0

3 years ago

Please help, I really don’t understand this!!!

kap26 [50]

Analysing the Question:

We are given the balanced equation:

C₆H₁₂O₆ + 6O₂→ 6CO₂ + 6H₂O

from this equation, we can say that: for every 1 mole of Glucose, we need 6 moles of Oxygen

Moles of Glucose used in the reaction:

Molar mass of Glucose = 180 grams / mol

Given mass of Glucose = 1 gram

Mole of Glucose = Given mass / Molar mass

Moles of Glucose = 1 / 180 moles

Mass of Oxygen required:

We know that for every mole of Glucose, we need 6 moles of Oxygen

So, for 1/180 moles of Glucose, we need 6 / 180 = 1 / 30 moles of Oxygen

Mass of 1 / 30 moles of Oxygen:

Mass = Molar mass * number of moles

Mass of Oxygen = 32 * 1/30

Mass of Oxygen = 32 / 30

Mass of Oxygen = 1.06 grams

5 0

3 years ago