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VMariaS [17]
3 years ago
10

Is 23 a prime number

Mathematics
1 answer:
Gekata [30.6K]3 years ago
3 0

Answer:

<h2><u>Yes</u></h2><h2><u></u></h2>

Step-by-step explanation:

A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself. A natural number greater than 1 that is not prime is called a composite number.

You might be interested in
Which line shows the graph of y = 4x - 5 reflected over the y-axis?
elena-14-01-66 [18.8K]

Answer:

The line y = -4x - 5 shows the reflection over the y-axis.

From the attached graph, the blue line i.e. y = -4x-5 represents the reflection over the y-axis.

Step-by-step explanation:

When we reflect a line function over the y-axis, all we need is to negate the x-coordinate or value of 'x', while y-coordinate or y-value remains the same.

Given the function

y = 4x-5

replace x with -x

y = 4(-x) - 5

y = -4x - 5

Thus, the line y = -4x - 5 shows the reflection over the y-axis.

From the attached graph, the blue line i.e. y = -4x-5 represents the reflection over the y-axis.

From the graph, it is clear that that that x-coordinate of y = 4x-5 is negated.

5 0
3 years ago
Which property of equality would be used to solve 3x= 81?
Inga [223]

Answer:

divison

Step-by-step explanation:

3x=81

3x/3=81/3

6 0
3 years ago
Orange M&amp;M’s: The M&amp;M’s web site says that 20% of milk chocolate M&amp;M’s are orange. Let’s assume this is true and set
SOVA2 [1]

Answer:

The correct option is (A).

Step-by-step explanation:

Let <em>X</em> = number of orange  milk chocolate M&M’s.

The proportion of orange milk chocolate M&M’s is, <em>p</em> = 0.20.

The number of candies in a small bag of milk chocolate M&M’s is, <em>n</em> = 55.

The event of an milk chocolate M&M being orange is independent of the other candies.

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 55 and <em>p</em> = 0.20.

The expected value of a Binomial random variable is:

E(X)=np

Compute the expected number of orange  milk chocolate M&M’s in a bag of 55 candies as follows:

E(X)=np

         =55\times 0.20\\=11

It is provided that in a randomly selected bag of milk chocolate M&M's there were 14 orange ones, i.e. the proportion of orange milk chocolate M&M's in a random bag was 25.5%.

This proportion is not surprising.

This is because the average number of orange milk chocolate M&M’s in a bag of 55 candies is expected to be 11. So, if a bag has 14 orange milk chocolate M&M’s it is not unusual at all.

All unusual events have a very low probability, i.e. less than 0.05.

Compute the probability of P (X ≥ 14) as follows:

P(X\geq 14)=\sum\limits^{55}_{x=14}{{55\choose x}0.20^{x}(1-0.20)^{55-x}}

                 =0.1968

The probability of having 14 or more orange candies in a bag of milk chocolate M&M’s is 0.1968.

This probability is quite larger than 0.05.

Thus, the correct option is (A).

4 0
3 years ago
F(x)=2log(-1/2x-1)+1
Annette [7]

Answer:

i am sorry i dont now the answer but thx for the 14 point

love  unkown name

Step-by-step explanation:

3 0
2 years ago
Describe the graph of y = 3x2 and compare it with the graph of y=x^2.
professor190 [17]

Answer:

y=-x^2 is just y=x^2 reflected over the x-axis. In other words, the parabola is upside-down.

Step-by-step explanation:

8 0
3 years ago
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