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3 years ago

Is 23 a prime number

Mathematics

1 answer:

Gekata [30.6K]3 years ago

3 0

Answer:

Step-by-step explanation:

A prime number is a natural number greater than 1 that has no positive divisors other than 1 and itself. A natural number greater than 1 that is not prime is called a composite number.

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Is is square root of 1.6875 a rational number

mamaluj [8]

Question:

Is square root of 1.6875 a rational number ?

Answer:

Square root of 1.6875 a rational number is not a rational number

Solution:

Given that we have to find square root of 1.6875 and determine if it is rational number or not

Let us first find square root of 1.6875

$\sqrt{1.6875} = 1.29903810568$

Let us understand about rational number

A rational number is a number that can be expressed as a fraction (ratio) in the form $\frac{p}{q}$ where p and q are integers and q is not zero.

When a rational number fraction is divided to form a decimal value, it becomes a terminating or repeating decimal.

So the number 1.29903810568 is not a rational number

In other words we can say,

Only the square roots of square numbers are rational. Here 1.6875 is not a perfect square. So it is not rational number

4 0

3 years ago

1/3x + 4 = 10 what is x

nydimaria [60]

Answer:

X = -13/10

Step-by-step explanation:

5 0

3 years ago

Through: (4, -1), parallel to y = -3/4x

Arada [10]

Is this a algebra question? I just want to know?

8 0

2 years ago

A right triangle has a leg of 11 cm and a hypotenuse of 17 cm.

Vedmedyk [2.9K]

The answer would be the second option, 13.0 cm.

To find the missing length of the leg, you would use the pythagorean theorem and substitute your inputs in.

a^2+b^2=c^2
11^2+b^2=17^2
121+b^2=289
b^2=168
b=12.96
b=13.0 cm (rounded up)

4 0

3 years ago

Read 2 more answers

Product of two natural numbers p and q is 590 and their hcf is 59. how many set of values of p and q is possible

djverab [1.8K]

$\text{Let the product of two natural numbers p and q is 590, and their HCF is 59}\\
\\
\text{we know that the product of LCM and HCF of any two numbers is equal}\\
\text{to the product of the numbers. that is}\\
\\
\text{HCF}\times \text{ LCM}=p\times q\\
\\
\Rightarrow 59 \times \text{LCM}=590\\
\\
\Rightarrow \text{LCM}=\frac{590}{59}\\
\\
\Rightarrow \text{LCM}=10\\
\\
\text{for any two natural numbers, their Least Common Multiple (LCM) is always}$

$\text{greater than their HCF.}\\
\\
\text{but here we can see that }LCM$

Hence there is no such natural numbers exist.

7 0

3 years ago