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inna [77]
2 years ago
11

Which property of equality would be used to solve 3x= 81?

Mathematics
1 answer:
Inga [223]2 years ago
6 0

Answer:

divison

Step-by-step explanation:

3x=81

3x/3=81/3

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What is the y intercept of the line -4x + 6y = -12?
snow_lady [41]
  -4x + 6y = -12
-4(0) + 6y = -12
     0 + 6y = 12
           <u>6y</u> = <u>12</u> 
            6      6
             y = 2

The y-intercept of the equation is 2.
6 0
3 years ago
Solve this equation 8-x2= -17
Dominik [7]

Answer:

x=25/2

Step-by-step explanation:

8-2x-8=-17-8

-2x=-25

-2x/2= -25/2

7 0
3 years ago
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A rectangle has a length that is three feet more than twice it's width. The perimeter of the rectangle is 78 feet. State the val
ivann1987 [24]

Let the width of the rectangle be 'w'

According to the question length of the rectangle (l) is three feet more than twice it's width;

\longrightarrow l = (2w + 3) ft

Perimeter of rectangle = 78 ft

Formula of perimeter of rectangle = 2(Length + Width)

So,

\rm \implies 2(Length + Width) = 78 \\  \\  \rm \implies 2(2w + 3 + w) = 78 \\  \\  \rm \implies 2(3w + 3) = 78 \\  \\  \rm \implies 2 \times 3(w + 1) = 78 \\  \\  \rm \implies 6(w + 1) = 78 \\  \\  \rm \implies w + 1 =  \dfrac{78}{6}  \\  \\  \rm \implies w + 1 = 13 \\  \\  \rm \implies w = 13 - 1 \\  \\  \rm \implies w = 12 \: ft

\therefore Width of the rectangle (w) = 12 ft

3 0
3 years ago
Insert geometric means in each geometric sequence.
Digiron [165]

Answer:

\underline{192}, 24, \underline{3}, \underline{\dfrac{3}{8}}, \dfrac{3}{64}

\underline{\dfrac{1}8}, \dfrac{1}{4}, \dfrac{1}{2}, \underline{1}

81, \underline{27, 9, 3, 1},\dfrac{1}{3}

Step-by-step explanation:

Given the Geometric sequences:

1. ___, 24, ___, ___, 3/64

2. ___, 1/4, 1/2, ___

3. 81, ___, ___, ___, ___, 1/3

To find:

The values in the blanks of the given geometric sequences.

Solution:

First of all, let us learn about the n^{th} term of a geometric sequence.

a_n=ar^{n-1}

Where a is the first term and

r is the common ratio by which each term varies from the previous term.

Considering the first sequence, we are given the second and fifth terms of the sequences.

Applying the above formula:

ar = 24\\ar^4 = \dfrac{3}{64}

Solving the above equation:

r = \dfrac{1}{8}

Therefore, the sequence is:

\underline{192}, 24, \underline{3}, \underline{\dfrac{3}{8}}, \dfrac{3}{64}

Considering the second given sequence:

ar = \dfrac{1}{4}\\ar^2 = \dfrac{1}{2}\\\text{Solving the above equations}, r = 2

Therefore, the sequence is:

\underline{\dfrac{1}8}, \dfrac{1}{4}, \dfrac{1}{2}, \underline{1}

Considering the third sequence:

a = 81\\ar^5=\dfrac{1}{3}\\\Rightarrow r = 3

Therefore, the sequence is:

81, \underline{27, 9, 3, 1},\dfrac{1}{3}

5 0
3 years ago
Complete this 5x^2+16x+11
snow_lady [41]
Do you want the answer or the procedure?
4 0
3 years ago
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