Ask question

Ask question

All categories

3 years ago

14

2. 20% of what number is 15

1 answer:

Ann [662]3 years ago

3 0

Answer:

75

20 percent (calculated percentage %) of what number equals 15? Answer: 75

You might be interested in

1. Solve: 9^2x + 1 = 9^3x – 2

katovenus [111]

Answer:

c

Step-by-step explanation:

my dads friend died ;-;

4 0

3 years ago

Read 2 more answers

What’s equivalent to 16 divided by 10

Nitella [24]

Answer:

32/20=1.6

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Which is the correct algebraic expression for the phrase, 14 more pickles than the first jar?

KIM [24]

Answer:A

Step-by-step explanation:

6 0

3 years ago

What is the value of 4 1/3Ã·1/9?Enter your answer as a fraction in simplest form, like this: 3/14

Vlada [557]

Hey there!

$\bold{4\frac{1}{3}\times\frac{1}{9}}$
$\bold{4\frac{1}{3}=\frac{13}{3}}$
$\bold{\frac{13}{3}(\frac{1}{9})}$
$\bold{13\times1=13}$
$\bold{9\times3=27}$
$\boxed{\boxed{\bold{Answer:\frac{13}{27} }}}$

Good luck on your assignment and enjoy your day!

~ $\bold{LoveYourselfFirst:)}$

8 0

3 years ago

A box contains 5 red balls, 6 white balls and 9 black balls. Two balls are drawn at

valina [46]

Answer:

$P(Same)=\frac{61}{190}$

Step-by-step explanation:

Given

$Red = 5$

$White = 6$

$Black = 9$

Required

The probability of selecting 2 same colors when the first is not replaced

The total number of ball is:

$Total = 5 + 6 + 9$

$Total = 20$

This is calculated as:

$P(Same)=P(Red\ and\ Red) + P(White\ and\ White) + P(Black\ and\ Black)$

So, we have:

$P(Same)=\frac{n(Red)}{Total} * \frac{n(Red) - 1}{Total - 1} + \frac{n(White)}{Total} * \frac{n(White) - 1}{Total - 1} + \frac{n(Black)}{Total} * \frac{n(Black) - 1}{Total - 1}$

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

$P(Same)=\frac{5}{20} * \frac{5 - 1}{20- 1} + \frac{6}{20} * \frac{6 - 1}{20- 1} + \frac{9}{20} * \frac{9- 1}{20- 1}$

$P(Same)=\frac{5}{20} * \frac{4}{19} + \frac{6}{20} * \frac{5}{19} + \frac{9}{20} * \frac{8}{19}$

$P(Same)=\frac{20}{380} + \frac{30}{380} + \frac{72}{380}$

$P(Same)=\frac{20+30+72}{380}$

$P(Same)=\frac{122}{380}$

$P(Same)=\frac{61}{190}$

4 0

3 years ago