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kondor19780726 [428]
3 years ago
13

What is the solution to the system of equations graphed below? y = x - 2 y = 4x - 5

Mathematics
1 answer:
ololo11 [35]3 years ago
6 0
There are 3 available methods - Substitution , Elimination and <span>Matrix.  

</span>The substitution<span> method is used to eliminate one of the variables by replacement. 
</span>
The elimination method<span> is used for solving linear systems. 
</span>
<span>A Matrix is an array of numbers. 
</span>
Lets use Substitution to solve this system. 

x-2=4x-5 

-2=4x-5-x 

-2=(4x-x)-5&#10;&#10; &#10; 

-2=3x-5 

-2+5=3x 

3=3x 

3=3x / 3 

x=1 

Now substitute <span>x=1  
</span>
y=x-2 

y=1-2&#10;&#10; &#10; 

y=-1&#10;&#10; 

Hence - x=1&#10; &#10;y=-1 

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The mean of 15 numbers is 12. An extra number is included and the mean increases to 13. What the extra number?
Studentka2010 [4]

Answer: 28

Step-by-step explanation:

The mean of 15 numbers = 12

Then , the sum of the numbers = 12x15 = 180

Let the extra number included be x , then

The new sum = x + 180

And the new total number will increase from 15 to 16

new mean = 13 , so we have :

\frac{x+180}{16} = 13

x+ 180 = 16(13)

x + 180 = 208

x = 208 - 180

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therefore , the extra number is 28

5 0
3 years ago
An Air Conditioner uses 850 Watts of electricity and local emissions from electricity produce 1.37 pounds of CO2 per kWh. If you
Zina [86]

Answer: 6,987,000 pounds fo CO₂ per kWh.

Step-by-step explanation: <u>Quilowatt</u>-<u>hour</u> <u>(kWh)</u> is a unit of energy that measures the amount of energy expended in 1 hour.

The AC uses 850 Watts, which in kW is 850,000 kW

If you leave the AC on for 6 hours, it will consume

850,000(6) = 5,100,000 kWh

Eletricity produces 1.37 pounds of CO₂ per kWh, then in 5,100,000 kWh:

1.37 \frac{pounds}{kWh}.(5,100,000kWh) = 6,987,000 pounds

If you open a window for 6 hours, you would keep 6,987,000 pounds of CO₂ for entering the atmosphere.

7 0
3 years ago
What equation is graphed in this figure?
ziro4ka [17]
The graph intersect the y axis in (0,1)
⇒ if x=0 ⇒ y=1

y+2= - 3/2(x-2)
if x=0 ⇒ y+2= - 3/2*(-2)=3 ⇒ y=1



when y=0 ⇒x<1
2= - 3/2(x-2)
2= -3/2x+3
2-3=-3/2x
x=-1:(-3/2)=2/3 <1
⇒ The answer is y+2= - 3/2(x-2)

4 0
3 years ago
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