Given that in a trianlgle the sides AB, BC, CA are in the ratio 3:4:6.
Let AB = 3k, BC = 4k and CA = 6k.
Then perimeter =3k+4k+6k = 13k
M, N, K are mid points of the sides.
By mid point theorem MN = 3k/2, NK = 4k/2 and KM = 6k/2
Hence perimeter of MNK = 13k/2 =5.2 (given)
Solve for k
k=2(5.2)/13 = 0.8
Hence sides are
AB = 3k = 3(0.8) = 2.4 in
BC = 4k= 3.2 in
CA = 4.8 in
Answer:
D. 3y+1
Step-by-step explanation:
The coefficient is the number in front of the variable
3y has a coefficient of 3
3 ( y-6) has a factor of 3 since it is multiplied by the other term ( y-6)
Step-by-step explanation:
(a) the value of p that makes the lines parallel :
=> -4/-p = -5/7
5p = 7×(-4)
5p = -28
p = -28/5 = -5.6
(b) the value of p that makes the lines perpendicular :
=> -4/-p = -1 ÷ (-5/7)
4/p = 7/5
7p = 4×5
7p = 20
p = 20/7 = 2.86
The total measure of interior angles of a triangle is 180°. with this in mind and if we already know to of the angles, then all we have to do is subtract the sum of the other two angles from 180°. so 60°+80°=140°. 180°-140°=40°. so the measure of the third angle is 40°. hope this helps!
Answer:
$49
Step-by-step explanation:
70 x 30%
70 x 0.3
21
70 - 21
49
