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kifflom [539]
3 years ago
10

Round 253.5198 to the nearest thousandth

Mathematics
2 answers:
kipiarov [429]3 years ago
4 0

Answer:

253.520

Step-by-step explanation:

Let us see what is the thousandths place...

It is the third digit to the right.

253.5198 rounded is about

253.520.

I can tell because you take the thousandths place, look at the one to the right of it, then if it is greater than 5, you make the thousandths place greater. Since it's a 9, you move the extra 10 thousandths to the next thing- the hundredths. and you get 253.520.

strojnjashka [21]3 years ago
3 0
It would be 253.520 (or just 253.52) when rounding to the nearest thousandth.
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Answer: 75%

Step-by-step explanation:

Height given :

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Which problem would you use the following proportion to solve for? = what is 40% of 24? what percent is 24 of 40? twenty-four is
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LiRa [457]

The answer can not be found from the given information

Step-by-step explanation:

Two different types of tea are sold in your store

  • You know 100 cups of tea were sold
  • One type sold 5 times as much as the other type

We need to find how much of each type of tea were sold

Assume that the two types are x and y

∵ x represents one type of tea

∵ y represents the other type of tea

∵ 100 cups of tea where sold

- Add x and y, then equate the sum by 100

∴ x + y = 100 ⇒ (1)

∵ x type is 5 times as much as y type

∴ x = 5y ⇒ (2)

Now we have a system of equations to solve it

Substitute x in equation (1) by equation (2)

∴ 5y + y = 100

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∴ y = 16.67

<em>But you know number cups must be whole numbers</em>

The number cups can be 102 <em>OR</em> one type is 4 times as much as the other type

If the number of cups is 102, then

85 cups of one type and 17 cups of the other type were sold

If one type is 4 times as much as the other type, then

80 cups of one type and 20 cups of the other type were sold

The answer can not be found from the given information

Learn more:

You can learn more about the system of equations in brainly.com/question/2115716

#LearnwithBrainly

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