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2 years ago

2(4)-5=

Mathematics

2 answers:

pashok25 [27]2 years ago

7 0

2 times 4 is 8 and u subtract 5 so the answer is 3

Step2247 [10]2 years ago

4 0

Answer:

Step-by-step explanation:

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Alphabet cutouts come in packages of 6 sheets for $8. How much does Tanesha spend on alphabet cutouts if she need 72 sheets?

Darina [25.2K]

Hey there! :)

Answer:

$96 spent.

Step-by-step explanation:

Set up a proportion to determine the amount spend for 72 sheets. Express it in sheets/amount spent:

$\frac{6}{8} = \frac{72}{x}$

Cross multiply:

6 · x = 8 · 72

6x = 576

Divide:

x = $96 spent for 72 sheets.

4 0

3 years ago

Read 2 more answers

HELP I WILL GIVE ALl MY POINTS NEXT QUESTION TO TH PERSON WHO ANSWERS RIGHT HELPP

djverab [1.8K]

Answer:

Mixed Fraction -

$1 \frac{5}{8}$

7 0

2 years ago

Calculate the unshaded part

valina [46]

Answer:

4×3=12

answer=12

Step-by-step explanation:

2.5 is the diameter so you don't use that but

if you want the area it is 12

if you want the perimeter it

will be 3+3+4+4

Which is 6+8=14

4 0

3 years ago

At a certain time of day, a tree that is x meters tall casts a shadow that is x−46x−46 meters long. if the distance from the top

Alexus [3.1K]

By the Pythagorean theorem,
.. x^2 +(x -46)^2 = (x +4)^2
.. 2x^2 -92x +2116 = x^2 +8x +16
.. x^2 -100x +2100 = 0
.. (x -50)^2 -400 = 0
.. x = 50 ±20 . . . . . only x=70 makes any sense in the problem

The height, x, of the tree is 70 meters.

5 0

3 years ago

Find the function of which is the solution of 36y"-48y'-48y=0 with initial conditions y1(0)=1. y1'(0)=0

lilavasa [31]

Answer:

$y=\frac{1}{4} e^{2x}+\frac{3}{4} e^{-\frac{2}{3}x }$

Step-by-step explanation:

Let, $D=\frac{d}{dx}$

Now, us simplify the given differential equation and write it in terms of D,

$36y''-48y'-48y=0$

or, $3y''-4y'-4y=0$

or, $(3D^2-4D-4)y=0$

We have our auxiliary equation:

$3D^2-4D-4=0$

or, $(3D+2)(D-2)=0$

or, $D=2, - \frac{2}{3}$

Therefore our solution is,

$y=Ae^{2x}+Be^{- \frac{2}{3}x}$

and, $y'=2Ae^{2x}-\frac{2}{3}Be^{\frac{2}{3}x }$

Applying the boundary conditions, we get,

$A+B=1$

$2A-\frac{2}{3}B=0$

Solving them gives us,

$A=\frac{1}{4} ,B=\frac{3}{4}$

Hence,

$y=\frac{1}{4} e^{2x}+\frac{3}{4} e^{-\frac{2}{3}x }$

4 0

3 years ago