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Paul [167]
3 years ago
6

Shelby will take a total of 6 tests. On the first 5 tests, her scores were: 80, 85, 73, 78, 90. If she wants a mean grade of 80,

what does Shelby have to score on her 6th test?
Mathematics
1 answer:
Andrew [12]3 years ago
4 0

Answer:

74

Step-by-step explanation:

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What is the answer to this question?
irina [24]

Answer:

1. \frac{33}{40}  

2. \frac{19}{35}

Step-by-step explanation:

1. (\frac{5}{8} * \frac{5}{5}) + (\frac{1}{5} * \frac{8}{8}) = \frac{33}{40}

8 0
3 years ago
Anne has worn a black shirt on 6 of the last 20 days. Considering this
Stels [109]

Answer:

3

Step-by-step explanation:

Considering she wore a black shirt 6 times in 20 days will give you the statistic of 3/10. If the question is about the next 10 days then she will wear 3 black shirts. (It's also 1/2 of the original question.)

7 0
3 years ago
For a certain casino slot machine, the odds in favor of a win are given as 17 to 83. Express the indicated degree of likelihood
balandron [24]

Step-by-step explanation:

83P (E)=17-17P (E),

P (E)=17/100=0.17

8 0
3 years ago
A simple random sample of the weights of 59 green candies has a mean of 0.8635 g. Assume that σ is known to be 0.0565 g. Assume
mina [271]

Solution: We are given:

\mu=0.8635

\sigma=0.0565

n=59

We need to find the test statistic in order to test the claim that the mean weight of all green candies is equal to 0.8535

We know that the test statistic is:

z=\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}}}

        =\frac{0.8535-0.8635}{\frac{0.0565}{\sqrt{59}}}

        =\frac{-0.01}{0.007355673}

        =-1.36

Therefore, the test statistic is z=-1.36

Hence the option -1.36 is correct.

6 0
3 years ago
Read 2 more answers
What goes into both 95 and 78?
MArishka [77]
You might want to factor both numbers and then look to see what factor or factors is common to both:

95 = 5*19 (no other factors)

78 = 39*2  =  3*13*2

Doesn't appear that there are any common factors!  Thus, 1 is the only integer that divides into both 95 and 78 evenly.


8 0
3 years ago
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