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34kurt
3 years ago
5

The center of a circle is (4, 6), and an endpoint of a diameter is (2, 5). What is the other endpoint of the diameter?

Mathematics
2 answers:
valentinak56 [21]3 years ago
3 0
Consider this option:
1. if the point (4;6) is the centre of the circle and the point (2;5) is the first endpoint of its diameter, then point (4;6) is the middle point of the diameter (it means that is the middle between the 1st and the 2d endpoints of diameter).
2. using the property described above:
for x of the 2d endpoint of the diameter: x=4*2-2=6;
for y of the 2d endpoint of the diameter: y=6*2-5=7.

answer: (6;7)
Vika [28.1K]3 years ago
3 0

Answer:

(6,7)

Step-by-step explanation:

The center of a circle is (4, 6), and an endpoint of a diameter is (2, 5)

Since center is the mid point of two end points of diameter .

So, we will use mid point formula

(x,y)=(4,6)

(x_1,y_1)=(2,5)

Mid point formula : x =\frac{x_1+x_2}{2} and y =\frac{y_1+y_2}{2}  

Substitute the values

4 =\frac{2+x_2}{2} and 6 =\frac{5+y_2}{2}  

8 =2+x_2 and 12 =5+y_2  

6=x_2 and 7=y_2  

Thus [tex](x_2,y_2)=(6,7)/tex]

Thus the other endpoint of the diameter is (6,7)

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So the number of bags is 12

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Read 2 more answers
(i) 3 (a + 5b) + a (a + 4) (ii) y (10 - y) + 3 (y - 2) (iii) 2 (8a - 5b) + 3 (5a - 12) (iv) 3 (y - 3) + ( 8 - 6y + x) (v) a (a -
AveGali [126]

Answer:

3 (a + 5b) + a (a + 4)  = a^2 + 7a + 15b

y (10 - y) + 3 (y - 2)  = - y^2+13y - 6

2 (8a - 5b) + 3 (5a - 12)  = 31a -10b  - 36

3 (y - 3) + ( 8 - 6y + x) = -3y + x-1

a (a - 2b) + b (b + 2a - c) =a^2  + b^2  - bc

5 (x - y + z) + (4x + 3y) =9x - 2y +5z

Step-by-step explanation:

Solving (i):

3 (a + 5b) + a (a + 4)

Open brackets

3 (a + 5b) + a (a + 4)  = 3a + 15b + a^2 + 4a

Collect like terms

3 (a + 5b) + a (a + 4)  = a^2 + 4a+3a + 15b

3 (a + 5b) + a (a + 4)  = a^2 + 7a + 15b

Solving (ii)

y (10 - y) + 3 (y - 2)

Open bracket

y (10 - y) + 3 (y - 2)  = 10y - y^2 + 3y - 6

Collect like terms

y (10 - y) + 3 (y - 2)  = - y^2+10y  + 3y - 6

y (10 - y) + 3 (y - 2)  = - y^2+13y - 6

Solving (iii)

2 (8a - 5b) + 3 (5a - 12)

Open bracket

2 (8a - 5b) + 3 (5a - 12)  = 16a -10b + 15a - 36

Collect like terms

2 (8a - 5b) + 3 (5a - 12)  = 16a+ 15a -10b  - 36

2 (8a - 5b) + 3 (5a - 12)  = 31a -10b  - 36

Solving (iv)

3 (y - 3) + ( 8 - 6y + x)

Open bracket

3 (y - 3) + ( 8 - 6y + x) = 3y - 9 + 8 - 6y + x

Collect like terms

3 (y - 3) + ( 8 - 6y + x) = 3y  - 6y + x- 9 + 8

3 (y - 3) + ( 8 - 6y + x) = -3y + x-1

Solving (v):

a (a - 2b) + b (b + 2a - c)

Open bracket

a (a - 2b) + b (b + 2a - c) =a^2 - 2ab + b^2 + 2ab - bc

Collect like terms

a (a - 2b) + b (b + 2a - c) =a^2 + 2ab- 2ab + b^2  - bc

a (a - 2b) + b (b + 2a - c) =a^2  + b^2  - bc

Solving (vi)

5 (x - y + z) + (4x + 3y)

Open brackets

5 (x - y + z) + (4x + 3y) =5x - 5y +5z+4x +3y

Collect like terms

5 (x - y + z) + (4x + 3y) =5x +4x +3y- 5y +5z

5 (x - y + z) + (4x + 3y) =9x - 2y +5z  

6 0
3 years ago
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