Answer:
Step-by-step explanation:
<h3>a)</h3>The function is continuous for x > 0 . The derivative is defined on that interval and is equal to ...
f'(x) = -2x . . . . . for x > 0
Then at x = 1, the derivative is ...
f'(1) = -2(1)
f'(1) = -2
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<h3>b)</h3>The function has a jump discontinuity at x=0, so the derivative does not exist at that point. A condition for the existence of the derivative is that the function is continuous at the point of interest.
Incomplete Question the complete Qs is
Which of the following is a correct equation for the line passing through the point (-2,1) and having slope m = 1/2?
a: y=1/2x+2
b: y=-2x+1/2
c: x-2y=-4
d: y-1=1/2(x+2)
Answer:
The Correct option is c. x-2y=-4
Therefore the correct equation for the line passing through the point (-2,1) and having slope m= 1/2 is
Step-by-step explanation:
Given:
point A(x₁, y₁)=(-2,1)
To Find:
Equation of Line =?
Solution:
Equation of a line passing through a points A( x₁ , y₁) and having slope m is given by the formula,
i.e equation in point - slope form
Now on substituting the slope and point A( x₁ , y₁) ≡ ( -2 , 1) we get
As required
Therefore the correct equation for the line passing through the point (-2,1) and having slope m= 1/2 is