3 years ago

Given the function f(x)=-3x^3+9x^2-2x+3 what part of the function indicates that the left end starts at the top of the graph

1 answer:

lina2011 [118]3 years ago

3 0

Given the function f(x)=-3x^3+9x^2-2x+3 what part of the function indicates that the left end starts at the top of the graph

The negative sign in the cubed term.

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Answer: $\frac{5}{4}$

Step-by-step explanation:

Given

$\cos \theta =\frac{-3}{5}$

and $\theta$ lies between

$90^{\circ}$

and for this $\theta$ , $\sin$ and $\text{cosec}$ is Positive as they lie in 2 nd Quadrant

$\sin ^2\theta +\cos ^2\theta =1$

$\sin ^2\theta =1-(\frac{-3}{5})^2$

$\sin ^2\theta =1-\frac{9}{25}$

$\sin ^2\theta =\frac{16}{25}$

$\sin \theta =\frac{4}{5}$

$\therefore \text{cosec}\ \theta =\frac{5}{4}$

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Good morning

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Answer:

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Step-by-step explanation:

2/3 = (2*4)/(3*4)=8/12

3/4 = (3*3)/(4*3)=9/12

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AnnyKZ [126]

Answer:

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