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elixir [45]
3 years ago
12

Solve using the quadratic formula. Select the correct solution. -7x=2x^2+9

Mathematics
1 answer:
gayaneshka [121]3 years ago
7 0

The answer to your question is B!

Have a wonderful day.

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30 POINTS HELP ME-
Ray Of Light [21]

Answer:

Number line graph with closed circle on 30 and shading to the right

because you already have 30 dollars and they need at least 120 but if they get more then 120 they can still hold the science fair.

THIS ANSWER ISN'T MINE. I TOOK IT FROM AN ANSWER TO THE SAME QUESTION ANOTHER USER POSTED.

4 0
3 years ago
Read 2 more answers
What is the sum in simplest form for 5/8+2/5
Bogdan [553]
(5/8)+(2/5)= 

so you need a common den so in this case its 40

so we multiply to get 40 like

(5/5)(5/8)+ (2/5)(8/8)=

25/40 + 16/ 40 = 41/40
5 0
4 years ago
Which represents the solution set of 5(x+5)<85
Sloan [31]
5x +25<85

5x < 60

x < 12
8 0
3 years ago
Id love some help!!!
timofeeve [1]
Answer : 12.56 inches²
Explanation :
Diameter is twice the radius.
Radius = 4 ÷ 2 = 2 inches
Area = 3.14r² = 3.14 × 2² = 12.56 inches²
3 0
2 years ago
Read 2 more answers
Rewrite 2tan3x in terms of tanx
blsea [12.9K]
2\tan3x=2\tan(2x+x)=\dfrac{2\tan2x+2\tan x}{1-\tan2x\tan x}

Use the same identity to expand \tan2x.

\tan2x=\tan(x+x)=\dfrac{\tan x+\tan x}{1-\tan x\tan x}=\dfrac{2\tan x}{1-\tan^2x}

\implies2\tan3x=\dfrac{2\dfrac{2\tan x}{1-\tan^2x}+2\tan x}{1-\dfrac{2\tan x}{1-\tan^2x}\tan x}
2\tan3x=\dfrac{2\tan x\left(\dfrac2{1-\tan^2x}+1\right)}{1-\dfrac{2\tan^2x}{1-\tan^2x}}
2\tan3x=\dfrac{2\tan x\left(2+1-\tan^2x\right)}{1-\tan^2x-2\tan^2x}
2\tan3x=\dfrac{2\tan x(3-\tan^2x)}{1-3\tan^2x}
4 0
3 years ago
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