Which rectangular equation represents the parametric equations x = 3t Superscript one-half and y = 6t?

Write quadratic equation whose roots are 1 and -3 and whose leading coefficient is 4

Mila [183]

Answer:

4x^2 + 8x - 12 = 0.

Step-by-step explanation:

We first write it in factor form.

4(x - 1)(x + 3) = 0

4(x^2 + 2x - 3) = 0

4x^2 + 8x - 12 = 0 (answer).

3 0

3 years ago

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In the rhombus m 1=15x, m 2=x+y, m 3=30z Find The Value of each variable

Sonbull [250]

First one m = .0666666
second one i don't know
third one is .1

4 0

3 years ago

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Round 7 3/8 to the nearest whole number?!?

DIA [1.3K]

Answer:

7

Step-by-step explanation:

Everything including 1/2 and above rounds up to the next whole number.

3/8 < 4/8

7 and 3/8 rounds to 7

5 0

3 years ago

The Price family and the Jenkins family each used their sprinklers last summer. The water output rate for the Price family's spr

PIT_PIT [208]

Set up two equations:

1st: P (for Price family) + J (for Jenkins family) = 45 hours

2nd: 20P + 35J = 1200 liters

Rewrite the first equation as P = 45 – J

Replace P in the second equation:

20(45-J) + 35J = 1200

Simplify:

900 -20J + 35J = 1200

900 +15J = 1200

Subtract 900 from both sides:

15J = 300

Divide both sides by 15:

J = 300/15

J = 20

Jenkins used theirs for 20 hours

Price used theirs for 45-20 = 25 hours.

7 0

3 years ago

Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X > 10) b. P(X > 20) c

GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(c) The value of P (X < 30) is 0.9502.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

$f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0$

The value of E (X) is 10.

The parameter λ is:

$\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10$

(a)

Compute the value of P (X > 10) as follows:

$P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679$

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

$P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353$