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postnew [5]
3 years ago
5

Which product is negative?

Mathematics
1 answer:
sveticcg [70]3 years ago
5 0

When I had these kinds of problems, I'd count how many negatives there were. If there more or less negatives to positives, then it is negative. If there's the same amount of positives and negatives, then it's positive since they cancel out! The answer to this is A. (-2)(-4)(8)(-1)=-64.

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16-5y=1-4y<br><img src="https://tex.z-dn.net/?f=16%20-%205y%20%3D%201%20-%204y" id="TexFormula1" title="16 - 5y = 1 - 4y" alt="1
MrRissso [65]
The answer is y=15 ..........
7 0
3 years ago
I will gave brainestly
hammer [34]

Answer:

Hello !

The solutions are: -8 , -4 , 6

Hope this helps !

3 0
3 years ago
Are (2,9) and (-3,-6) both on the line y = 4x + 6? If not, find an equation for the line that does pass through both points.
igor_vitrenko [27]

Answer:

no, y=3x+3

Step-by-step explanation:

plug both points into the equations:

  • 9=4*2 +6 -> 9=8+6, doesn't work
  • -6=4(-3)+6 -> -6=-6, works

one works but the other doesn't so now we find a line through both points

use the formula (y_2-y_1)/(x_2-x_1) to find the slope:

  • (-6-9)/(-3-2)=-15/-5=3

y=3x+b, plug in a point to find b:

  • 9=3(2)+b
  • 9=6+b
  • b=3
  • y=3x+3
7 0
3 years ago
Write the equation of the given circle.<br><br> center (1, -5)<br> radius of 10
Naddika [18.5K]

Answer:

(x-1)^2+(y+5)^2=100

Step-by-step explanation:

The equation of a circle has the following form:

(x-h)^2+(y-k)^2=r^2 where (h,k) is the center of a circle with radius r.

Our equation center is (1.-5) and radius is 10.

(x-1)^2+(y--5)^2=10^2

(x-1)^2+(y+5)^2=100



3 0
3 years ago
I hvae this for hw can anyone help me out rq?
AleksandrR [38]

Answer:

0 1 and 5

Step-by-step explanation:

Not 6 because its an open dot which means that 6 is not included

I hope this helps?

4 0
3 years ago
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