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USPshnik [31]
3 years ago
9

Identify the horizontal asymptote of f(x) = quantity 7 x plus 1 over quantity 2 x minus 9.

Mathematics
1 answer:
salantis [7]3 years ago
6 0
You just divide the leading coefficients, the answer is 7/2
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ryzh [129]

Answer:

b

Step-by-step explanation:

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3 years ago
Valerie is making identical quilts for herself and her sister. For each quilt she buys 5 yards of solid fabric and w yards of pr
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Valerie bought 18yrds of fabric. If she used 9yrds of fabric on her quilt, she will use another 9yrds on her sister's. The total is 18yrds.
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3 years ago
You are given the parametric equations x=2cos(θ),y=sin(2θ). (a) List all of the points (x,y) where the tangent line is horizonta
vladimir1956 [14]

Answer:

The solutions listed from the smallest to the greatest are:

x:  -\sqrt{2}   -\sqrt{2}  \sqrt{2}  \sqrt{2}

y:      -1         1     -1     1

Step-by-step explanation:

The slope of the tangent line at a point of the curve is:

m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }

m = -\frac{\cos 2\theta}{\sin \theta}

The tangent line is horizontal when m = 0. Then:

\cos 2\theta = 0

2\theta = \cos^{-1}0

\theta = \frac{1}{2}\cdot \cos^{-1} 0

\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right), for all i \in \mathbb{N}_{O}

\theta = \frac{\pi}{4} + i\cdot \frac{\pi}{2}, for all i \in \mathbb{N}_{O}

The first four solutions are:

x:   \sqrt{2}   -\sqrt{2}  -\sqrt{2}  \sqrt{2}

y:     1        -1        1     -1

The solutions listed from the smallest to the greatest are:

x:  -\sqrt{2}   -\sqrt{2}  \sqrt{2}  \sqrt{2}

y:      -1         1     -1     1

6 0
3 years ago
The sum of a number y and -3 is -8 .
Allushta [10]

Answer:

-5 IDS THE AANSERRRRR thanks

Step-by-step explanation:

3 0
3 years ago
Help 7th grade math pls
madam [21]

Answer:

1,455 feet

Step-by-step explanation:

Step 1:

1 : 75    Ratio Inches to Feet

Step 2:

1 : 75 = 19.4 : x   Equation

Answer:

x = 1,455  Multiply

Hope This Helps :)

4 0
3 years ago
Read 2 more answers
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