Answer
given,
![f(x) = \dfrac{-e^x}{x - 4}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Cdfrac%7B-e%5Ex%7D%7Bx%20-%204%7D)
to find the critical point of the given expression
fist differentiating the function
![f'(x) = -\dfrac{(x-4)e^x+ e^x}{(x - 4)^2}](https://tex.z-dn.net/?f=f%27%28x%29%20%3D%20-%5Cdfrac%7B%28x-4%29e%5Ex%2B%20e%5Ex%7D%7B%28x%20-%204%29%5E2%7D)
![f'(x) = \dfrac{-(x-4)e^x- e^x}{(x - 4)^2}](https://tex.z-dn.net/?f=f%27%28x%29%20%3D%20%5Cdfrac%7B-%28x-4%29e%5Ex-%20e%5Ex%7D%7B%28x%20-%204%29%5E2%7D)
![f'(x) = \dfrac{-e^x(x-3)}{(x - 4)^2}](https://tex.z-dn.net/?f=f%27%28x%29%20%3D%20%5Cdfrac%7B-e%5Ex%28x-3%29%7D%7B%28x%20-%204%29%5E2%7D)
now equating differential equation to zero
![\dfrac{e^x(-x+3)}{(x - 4)^2}=0](https://tex.z-dn.net/?f=%20%5Cdfrac%7Be%5Ex%28-x%2B3%29%7D%7B%28x%20-%204%29%5E2%7D%3D0)
![e^x(-x+3)=0](https://tex.z-dn.net/?f=%20e%5Ex%28-x%2B3%29%3D0)
now,
-x + 3 = 0 and eˣ ≠ 0
x = 3
the critical number will be equal to x = 3
![y = \dfrac{-e^3}{3 - 4}](https://tex.z-dn.net/?f=y%20%3D%20%5Cdfrac%7B-e%5E3%7D%7B3%20-%204%7D)
![y =e^3](https://tex.z-dn.net/?f=y%20%3De%5E3)
Answer:
23
Step-by-step explanation:
25.73−2.19
=25.73−2.19
=25.73+−2.19
=23.54
QT = RS
30 = 4x + 10
20 = 4x
x = 5
answer
x = 5 It's B. second choice