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yarga [219]
2 years ago
11

A jar contains 3 yellow and 7 green marbles. You randomly draw one marble from the jar then REPLACE it and randomly draw a secon

d marble. Find the probability that you draw a yellow marble first and then a green marble.
Mathematics
1 answer:
kap26 [50]2 years ago
3 0

3 yellow + 7 green = 10 total marbles.

The probability of picking a certain color is the number of that color over the total quantity.

Picking yellow would be 3 yellow / 10 total = 3/10

Picking green would be 7 green / 10 total = 7/10

To find the probability of doing both multiply the probability of each one by each other:

3/10 x 7/10 = 21/100

The answer would be 21/100

You might be interested in
3. A regular pentagon has a perimeter of 10x + 15. What is the length of che side?
Ivan

Answer:

C

Step-by-step explanation:

A pentagon has 5 sides. Given that it is a regular pentagon, these 5 sides are equal.

The perimeter is the total length of all the sides of the pentagon. Since these 5 sides are all equal, we can divide the perimeter by 5 to obtain the length of a side of the pentagon.

Perimeter= 10x +15

Length of each side

= (10x +15) ÷5

= 2x +3

5 0
3 years ago
What can be concluded if angle 1 =angle7
Maksim231197 [3]

From the information given in the question,
the only possible conclusion is:

              If angle 1 is measured and angle 7 is measured,
           the two measurements will be identical.

If angle 1 and angle 7 are related to a particular shape or drawing,
then additional conclusions may be possible, but we'd need to see
the shape or drawing.

8 0
3 years ago
Find the difference between the result of one sixth of product of 10 and 3 multiplied by 4 and 30
kherson [118]

Answer:

10 or -10,

Read the explanation

Step-by-step explanation:

Rewrite this problem as a numerical expression. As per the wording of this problem, there can be two expressions derived.

1.     ((\frac{1}{6}(10*3)*4)-30

2.     30-((\frac{1}{6}(10*3)*4)

Simplify, remember the order of operations. The order of operations is the sequence by which one is supposed to perform operations in a numerical expression. This order is the following:

1. Parenthesis

2. Exponents

3. Multiplication or division

4. Addition or Subtraction

Use this sequence when simplifying and solving the expression:

Expression 1

((\frac{1}{6}(10*3)*4)-30\\\\=((\frac{1}{6}(30)*4)-30\\\\=(5*4)-30\\\\=20 - 30\\\\= -10

Expression 2

30-((\frac{1}{6}(10*3)*4)\\\\=30-((\frac{1}{6}(30)*4)\\\\=30-(5*4)\\\\= 30-20\\\\= 10

6 0
3 years ago
Joe went to the hobby shop and bought 2 model sports cars at $8.95 each and some paints. If he spent a total of $23.65, what was
Gala2k [10]
Since he bought 2 model cars for $8.95 each, he bought both for $17.90. Now, subtract this from the total cost to get the cost of paint. $23.65-$17.90=$5.75. So, the total costs of paints are $5.75. Hope this helped!
8 0
3 years ago
A donut store has 11 different types of donuts. You can only buy a bag of 3 of them, where each donut has to be of a different t
MakcuM [25]

Answer:

165.

Step-by-step explanation:

Since repetition isn't allowed, there would be 11 choices for the first donut, (11 - 1) = 10 choices for the second donut, and (11 - 2) = 9 choices for the third donut. If the order in which donuts are placed in the bag matters, there would be 11 \times 10 \times 9 unique ways to choose a bag of these donuts.

In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type 3 \times 2 \times 1 = 6 times.

For example, if a bag includes donut of type x, y, and z, the count 11 \times 10 \times 9 would include the following 3 \times 2 \times 1 arrangements:

  • xyz.
  • xzy.
  • yxz.
  • yzx.
  • zxy.
  • zyx.

Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count 11 \times 10 \times 9 by 3 \times 2 \times 1 = 6 to find the actual number of donut combinations:

\begin{aligned} \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}.

Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of 3 objects from a set of 11 distinct objects:

\begin{aligned}\begin{pmatrix}11 \\ 3\end{pmatrix} &= \frac{11 !}{(11 - 3)! \times 3 !} \\ &= \frac{11 !}{8 ! \times 3 !} \\ &= \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}.

5 0
2 years ago
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