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svetoff [14.1K]
3 years ago
9

I don't understand rational and irrational numbers

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
4 0

A rational number is a number which can be expressed as a fraction whose numerator and denominator are both integers and whose denominator is not equal to zero. Rational numbers include all integers, fractions, mixed numbers, and some decimal numbers.

 

Note : All terminating and repeating decimal numbers are rational numbers because those numbers can be expressed as a fraction. On the other hand, a non repeating number and non terminating decimal, like square root of 2, is an irrational number.  


\dfrac{7}{16} \ as \ a \ decimal = 0.4375


Set \ up \ the \ long \ division. 


Calculate \ 70 \div 16, \ which \ is \ 4  \ with \ a \ remainder \ of \ 6.




Bring \ down \ 0, so \ that \ 60 \ is \ large \ enough \ to \ be  \ divided \ by \ 16.




Calculate \ 60 \div 16, which \ is \ 3 \ with \ a  \ remainder \ of \ 12.




Bring \ down \ 0, so \ that \ 120 \ is \ large \ enough \ to \ be \ divided \ by \ 16.




Calculate \ 120 \div 16, which \ is \ 7 \ with \ a \ remainder \ of \ 8.




Bring \ down \ 0, so \ that \ 80 \ is \ large \ enough \ to \ be \ divided \ by \ 16.



Calculate \ 80 \div 16, which \ is \ 5. 

<span>
</span>

Decimal = 0.4375&#10;

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Answer:

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Step-by-step explanation:

Factorize:

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<u>Factor Theorem</u>

If f(a) = 0 for a polynomial then (x - a) is a factor of the polynomial f(x).

Substitute x = 1 into the function:

\implies f(1)=2(1)^3-1^2+1-2=0

Therefore, (x - 1) is a factor.

As the polynomial is cubic:

\implies  f(x)=(x-1)(ax^2+bx+c)

Expanding the brackets:

\implies  f(x)=ax^3+bx^2+cx-ax^2-bx-c

\implies  f(x)=ax^3+(b-a)x^2+(c-b)x-c

Comparing coefficients with the original polynomial:

\implies ax^3=2x^3 \implies a=2

\implies (b-a)x^2=-x^2 \implies b-2=-1 \implies b=1

\implies -c=-2 \implies c=2

Therefore:

\implies  f(x)=(x-1)(2x^2+x+2)

Cannot be factored any further.

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