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maks197457 [2]
3 years ago
9

Question Progress

Mathematics
1 answer:
Arada [10]3 years ago
4 0
Girls are 4ft tall
Hi sir i just sent you an invite for a meeting at
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I can't seem to figure out the answer to #10. Any help? (Ignore my work)
sashaice [31]
First I think you need to find the angle of the sector. Since it is one hour, and a clock has 12 hours, you would divide 360 by 12 to get 30.  then you would do this:
(30/360)(2)(pi)(16)
you would get 8.37758041
8 0
4 years ago
D/-2 +5 = 14 what is d
mixer [17]

Answer:

d could be -18

Step-by-step explanation:

Add 5 on both sides

Multiply both sides by -2

3 0
3 years ago
Read 2 more answers
You are collecting a sample of 60 data points from a population that you know to follow an exponential distribution. It is not a
11111nata11111 [884]

Answer:

For the exponential distribution:

\mu = \frac{1}{\lambda}

\sigma^2 = \frac{1}{\lambda^2}

We know that the exponential distribution is skewed but the sample mean for this case using a sample size of 60 would be approximately normal, so then we can conclude that if we have a sample size like this one and an exponential distribution we can approximate the sample mean to the noemal distribution and indeed use the Central Limit theorem.

\bar X \sim N(\mu_{\bar X} , \frac{\sigma}{\sqrt{n}})

\mu_{\bar X} = \bar X

\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}

Step-by-step explanation:

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

For this case we have a large sample size n =60 >30

The exponential distribution is the probability distribution that describes the time between events in a Poisson process.

For the exponential distribution:

\mu = \frac{1}{\lambda}

\sigma^2 = \frac{1}{\lambda^2}

We know that the exponential distribution is skewed but the sample mean for this case using a sample size of 60 would be approximately normal, so then we can conclude that if we have a sample size like this one and an exponential distribution we can approximate the sample mean to the noemal distribution and indeed use the Central Limit theorem.

\bar X \sim N(\mu_{\bar X} , \frac{\sigma}{\sqrt{n}})

\mu_{\bar X} = \bar X

\sigma_{\bar X}= \frac{\sigma}{\sqrt{n}}

5 0
4 years ago
Can you answer it? I really need help Urgently!
Georgia [21]

Answer: D 3<x<infinity

Step-by-step explanation:

5 0
3 years ago
Suppose query Q1 obtains the median ml of a set S1 of values, and query Q2 obtains the median m2 of a subset S2 of S1. If m1 2,
kari74 [83]

Answer/explanation:

Suppose S1 is the number of patients above 35years receiving medical treatment, and S2 is the number of patients below 35 years receiving medical.

then, S1 not in S2 simply means patients that are not receiving medical treatment.

And If M1 < M2, it means a lower number of patients above 35years than the patients below 35years receive medical treatment.

8 0
3 years ago
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