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3 years ago

PLEASE ANSWER ASAP FOR BRAINLEST, REALLY EASY QUESTION!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

Tresset [83]3 years ago

8 0

Answer:

i think its 200

Step-by-step explanation:

balandron [24]3 years ago

5 0

Answer: 3.2%

Step-by-step explanation: i searched it up

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4 years ago

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3 years ago

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3 years ago

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Yuliya22 [10]

Answer:

Step-by-step explanation:

Given algebraic expression: 6x^3y+7x^2+5x+46x3y+7x2+5x+4

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3 years ago

In ΔUVW, w = 44 cm, u = 83 cm and ∠V=141°. Find the area of ΔUVW, to the nearest square centimeter.

Tema [17]

Answer:

$Area \approx 1149\ cm^2$

Step-by-step explanation:

<u>Given that:</u>

ΔUVW,

Side w = 44 cm, (It is the side opposite to $\angle W$ )

Side u = 83 cm (It is the side opposite to $\angle U$ )

and ∠V=141°

Please refer to the attached image with labeling of the triangle with the dimensions given.

Area of a triangle with two sides given and angle between the two sides can be formulated as:

$A = \dfrac{1}{2}\times a\times b\times sinC$

Where a and b are the two sides and

$\angle C$ is the angle between the sides a and b

Here we have a = w = 44cm

b = u = 44cm

and ∠C= ∠V=141

Putting the values to find the area:

$A = \dfrac{1}{2}\times 44\times 83\times sin141\\\Rightarrow A = \dfrac{1}{2} \times 3652 \times sin141\\\Rightarrow A =1826 \times 0.629\\\Rightarrow A \approx 1149\ cm^2$

So, the <em>area </em>of given triangle to the nearest square centimetre is:

$Area \approx 1149\ cm^2$

8 0

4 years ago