I didn't get all the part with the tiles, but here's the general answer:
given a polynomial

we have that
is a factor of
if and only if k is a root of
, i.e. if

So, given the polynomial

We can check if
is a factor by evaluating
:

So,
is not a factor.
Similarly, we can evaluate
to check if
are factors:

So, only
is a factor of 
Answer: all points
that satisfy
Step-by-step explanation:
The slope of the line is

So, substituting into point-slope form, the equation is

Therefore, all points
that satisfy
will lie on the same line.
Answer:
228
Step-by-step explanation:
We are adding 3 each time so general rule is
Tn= 3n + 3
Therefore
T= 3(75)+3
= 228
The equations give you information as to where to plot points.
For y = -x + 1, you know the slope is -1, and the line intersects the y-axis at (0, 1). The y-axis is the vertical line; to plot (0, 1), find 1 on the vertical line and mark it. Now, the slope is -1; that means the line will slope downwards. To plot more points, count 1 unit down from (0, 1) and 1 unit to the right. You should end up at (1, 0).Connect those and you have a line.
For y = -2x + 4, the slope is -2 (so it will also slope downwards), and the y-intercept is 4. Find (0, 4) and plot it. The -2 tells you to count 2 units down (instead of 1 like we did for the last equation) and 1 over. That is the second line.
I hope this helps.