3 years ago

Solve 15 ≥ -3x or 2/5x ≥ -2.

Mathematics

1 answer:

Lera25 [3.4K]3 years ago

8 0

Answer:

$15 \geqslant - 3x \\ \frac{15}{3} \geqslant - x \\ 5 \geqslant - x \\ - 5 \leqslant x$

$\frac{2}{5}x \geqslant - 2 \\ x \geqslant - 2 \times \frac{5}{2} \\ x \geqslant - 5$

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